Waves — Class 11 Physics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 11 Physics chapter "Waves" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 11 Physics chapter "Waves" — 8 important questions with detailed answers for CBSE board exam preparation.

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Key Questions Covered:

  1. A tuning fork vibrates at frequency 256 Hz. The speed of sound in air is 340 …
  2. Two coherent sound sources emit sound at 500 Hz. The speed of sound is 330 m/…
  3. A string of length 0.5 m and mass 10 g is fixed at both ends. When vibrating …
  4. + 5 more questions in the full chapter

Solutions Summary:

Question Status
A tuning fork vibrates at frequency 256 Hz. The speed of … ✓ Solved
Two coherent sound sources emit sound at 500 Hz. The spee… ✓ Solved
A string of length 0.5 m and mass 10 g is fixed at both e… ✓ Solved

Showing 3 of 8 questions

Q1: A tuning fork vibrates at frequency 256 Hz. The speed of sound in air is 340 m/s. Calculate (a) the wavelength, (b) the period of the wave.

Step 1: Wavelength using wave equation: v = fλ λ = v/f where v = speed of sound, f = frequency λ = 340/256 = 1.328 m ≈ 1.33 m Step 2: Period: T = 1/f = 1/256 = 0.00391 s ≈ 3.91 × 10⁻³ s = 3.91 ms Final Answer: (a) Wavelength = 1.33 m; (b) Period = 3.91 ms

Q2: Two coherent sound sources emit sound at 500 Hz. The speed of sound is 330 m/s. If the sources are 0.66 m apart, calculate the path difference for constructive and destructive interference.

Step 1: Calculate wavelength: λ = v/f = 330/500 = 0.66 m Step 2: For constructive interference: Path difference = nλ where n = 0, 1, 2, 3, ... For n = 0: Path difference = 0 For n = 1: Path difference = λ = 0.66 m For n = 2: Path difference = 2λ = 1.32 m Step 3: For destructive interference: Path ...

Q3: A string of length 0.5 m and mass 10 g is fixed at both ends. When vibrating in its fundamental mode, the frequency is 100 Hz. Calculate the tension in the string.

Step 1: For a string fixed at both ends, fundamental frequency: f₁ = (1/2L)√(T/μ) where T = tension, μ = linear mass density = mass/length, L = length Step 2: Rearrange for tension: T = 4L²f₁²μ Step 3: Calculate linear mass density: m = 10 g = 0.01 kg L = 0.5 m μ = m/L = 0.01/0.5 = 0.02 kg/m Ste...

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