Motion in a Straight Line — Class 11 Physics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 11 Physics chapter "Motion in a Straight Line" — 7 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 11 Physics chapter "Motion in a Straight Line" — 7 important questions with detailed answers for CBSE boar…

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Key Questions Covered:

  1. A car starts from rest and accelerates uniformly at 2 m/s² for 10 seconds, th…
  2. A ball is thrown vertically upward with an initial velocity of 20 m/s. Taking…
  3. Define instantaneous velocity and average velocity. A particle moves such tha…
  4. + 4 more questions in the full chapter

Solutions Summary:

Question Status
A car starts from rest and accelerates uniformly at 2 m/s… ✓ Solved
A ball is thrown vertically upward with an initial veloci… ✓ Solved
Define instantaneous velocity and average velocity. A par… ✓ Solved

Showing 3 of 7 questions

Q1: A car starts from rest and accelerates uniformly at 2 m/s² for 10 seconds, then moves with constant velocity. Draw the v-t graph for the motion and find the total distance covered in 15 seconds.

Given: Initial velocity u = 0 m/s (starts from rest) Acceleration a = 2 m/s² Time of acceleration t₁ = 10 s Total time = 15 s Part 1: Find velocity after 10 s Using v = u + at v = 0 + 2 × 10 = 20 m/s Part 2: Distance during acceleration (0 to 10 s) Using s = ut + (1/2)at² s₁ = 0 + (1/2) × 2 × (1...

Q2: A ball is thrown vertically upward with an initial velocity of 20 m/s. Taking g = 10 m/s², find (a) the time taken to reach maximum height (b) the maximum height (c) the velocity when it returns to the starting point.

Given: Initial velocity u = 20 m/s (upward, positive direction) Acceleration due to gravity g = -10 m/s² (downward, negative) Final velocity at maximum height v = 0 m/s Part (a): Time to reach maximum height Using v = u + at 0 = 20 + (-10)t 10t = 20 t = 2 s Part (b): Maximum height Using v² = u²...

Q3: Define instantaneous velocity and average velocity. A particle moves such that its position is given by x = 5t² + 3t + 2 (where x is in metres and t is in seconds). Find the instantaneous velocity at t = 2 s and average velocity from t = 0 to t = 2 s.

Definitions: Average velocity: Average velocity is the displacement divided by the total time taken. v_avg = Δx/Δt = (x₂ - x₁)/(t₂ - t₁) It represents the overall rate of change of position. Instantaneous velocity: Instantaneous velocity is the velocity at a particular instant of time. v_inst = dx...

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