Mechanical Properties of Fluids — Class 11 Physics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 11 Physics chapter "Mechanical Properties of Fluids" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 11 Physics chapter "Mechanical Properties of Fluids" — 8 important questions with detailed answers for CBS…

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Key Questions Covered:

  1. A hydraulic press has a small piston of area 5 cm² and a large piston of area…
  2. Mercury has a density of 13,600 kg/m³. Calculate the pressure exerted by a 76…
  3. A steel ball of radius 2 cm and density 8000 kg/m³ falls through a viscous me…
  4. + 5 more questions in the full chapter

Solutions Summary:

Question Status
A hydraulic press has a small piston of area 5 cm² and a … ✓ Solved
Mercury has a density of 13,600 kg/m³. Calculate the pres… ✓ Solved
A steel ball of radius 2 cm and density 8000 kg/m³ falls … ✓ Solved

Showing 3 of 8 questions

Q1: A hydraulic press has a small piston of area 5 cm² and a large piston of area 50 cm². A force of 100 N is applied on the small piston. Calculate the force exerted by the large piston on the load.

Step 1: In a hydraulic press, pressure is transmitted uniformly throughout the fluid. P = F/A = constant everywhere Step 2: Pressure on small piston = 100/(5 × 10⁻⁴) = 2 × 10⁵ Pa Step 3: Since pressure is same throughout: P = F_large/A_large 2 × 10⁵ = F_large/(50 × 10⁻⁴) F_large = 2 × 10⁵ × 50 × 1...

Q2: Mercury has a density of 13,600 kg/m³. Calculate the pressure exerted by a 76 cm column of mercury. Given: g = 10 m/s².

Step 1: Pressure due to a fluid column P = ρgh where ρ = density, g = acceleration due to gravity, h = height of column Step 2: Convert height to SI units: h = 76 cm = 0.76 m Step 3: Calculate pressure: P = 13,600 × 10 × 0.76 P = 136,000 × 0.76 P = 103,360 Pa ≈ 1.034 × 10⁵ Pa Step 4: In atmospher...

Q3: A steel ball of radius 2 cm and density 8000 kg/m³ falls through a viscous medium. The terminal velocity is 5 m/s. Calculate the coefficient of viscosity of the medium. (Density of medium = 1000 kg/m³)

Step 1: At terminal velocity, net force = 0 Weight = Buoyancy + Viscous drag mg = m'g + 6πηrv where η = coefficient of viscosity, r = radius, v = terminal velocity Step 2: Calculate weight of steel ball: Volume V = (4/3)πr³ = (4/3)π(0.02)³ = 3.35 × 10⁻⁵ m³ Mass m = ρ_steel × V = 8000 × 3.35 × 10⁻⁵ ...

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