Gravitation — Class 11 Physics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 11 Physics chapter "Gravitation" — 6 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 11 Physics chapter "Gravitation" — 6 important questions with detailed answers for CBSE board exam prepara…

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Key Questions Covered:

  1. State Newton's law of universal gravitation and derive the acceleration due t…
  2. The Moon has a mass of 7.35 × 10²² kg and radius 1.74 × 10⁶ m. Calculate the …
  3. Calculate the orbital velocity of a satellite in a circular orbit at a height…
  4. + 3 more questions in the full chapter

Solutions Summary:

Question Status
State Newton's law of universal gravitation and derive th… ✓ Solved
The Moon has a mass of 7.35 × 10²² kg and radius 1.74 × 1… ✓ Solved
Calculate the orbital velocity of a satellite in a circul… ✓ Solved

Showing 3 of 6 questions

Q1: State Newton's law of universal gravitation and derive the acceleration due to gravity at the Earth's surface.

Newton's Law of Universal Gravitation: Statement: Every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. Mathematical Form: F = G(m₁m₂)/r² Wh...

Q2: The Moon has a mass of 7.35 × 10²² kg and radius 1.74 × 10⁶ m. Calculate the acceleration due to gravity on the Moon's surface and compare it with Earth's gravity (g_earth = 10 m/s²).

Given: Mass of Moon M_m = 7.35 × 10²² kg Radius of Moon R_m = 1.74 × 10⁶ m G = 6.67 × 10⁻¹¹ N⋅m²/kg² g_earth = 10 m/s² (approximately) Part 1: Calculate acceleration due to gravity on Moon Using the formula: g_moon = GM_m/R_m² Step 1: Calculate numerator GM_m = 6.67 × 10⁻¹¹ × 7.35 × 10²² = 6.67 ×...

Q3: Calculate the orbital velocity of a satellite in a circular orbit at a height of 400 km above Earth's surface. (Mass of Earth = 6 × 10²⁴ kg, Radius of Earth = 6.4 × 10⁶ m, G = 6.67 × 10⁻¹¹ N⋅m²/kg²)

Given: Height above surface h = 400 km = 4 × 10⁵ m Mass of Earth M = 6 × 10²⁴ kg Radius of Earth R = 6.4 × 10⁶ m G = 6.67 × 10⁻¹¹ N⋅m²/kg² Find: Orbital velocity of the satellite Step 1: Determine orbital radius The satellite orbits at distance r from Earth's centre: r = R + h = 6.4 × 10⁶ + 4 × 1...

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