System of Particles and Rotational Motion — Class 11 Physics NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 11 Physics chapter "System of Particles and Rotational Motion" — 6 important questions with detailed answers for CBSE board exam preparation.
TL;DR: Free step-by-step NCERT solutions for Class 11 Physics chapter "System of Particles and Rotational Motion" — 6 important questions with detailed answe…
By Syllab.in · Updated
Key Questions Covered:
- Define centre of mass and moment of inertia. Explain their significance in ro…
- Calculate the moment of inertia of a solid cylinder of mass 10 kg and radius …
- Two particles of masses 3 kg and 5 kg are separated by a distance of 4 m. Fin…
- + 3 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| Define centre of mass and moment of inertia. Explain thei… | ✓ Solved |
| Calculate the moment of inertia of a solid cylinder of ma… | ✓ Solved |
| Two particles of masses 3 kg and 5 kg are separated by a … | ✓ Solved |
Showing 3 of 6 questions
Q1: Define centre of mass and moment of inertia. Explain their significance in rotational motion.
Centre of Mass Definition:
The centre of mass of a system is the point where the entire mass of the system can be considered to be concentrated for the purpose of analyzing translational motion. It is the average position of all the mass in the system.
For a system of n particles:
r_cm = (m₁r₁ + m₂...
Q2: Calculate the moment of inertia of a solid cylinder of mass 10 kg and radius 0.5 m about its central axis. Also calculate its rotational kinetic energy if it rotates at 100 rpm.
Given:
Mass of cylinder M = 10 kg
Radius R = 0.5 m
Rotational speed N = 100 rpm
Part 1: Moment of inertia of solid cylinder
For a solid cylinder rotating about its central axis:
I = (1/2)MR²
Substituting values:
I = (1/2) × 10 × (0.5)²
I = 5 × 0.25
I = 1.25 kg⋅m²
Part 2: Convert rpm to rad/s
An...
Q3: Two particles of masses 3 kg and 5 kg are separated by a distance of 4 m. Find the position of their centre of mass from the 3 kg mass.
Given:
Mass 1: m₁ = 3 kg
Mass 2: m₂ = 5 kg
Separation distance: d = 4 m
Find: Position of centre of mass from the 3 kg mass
Step 1: Set up coordinate system
Place the 3 kg mass at the origin (x = 0)
Place the 5 kg mass at x = 4 m
Step 2: Use centre of mass formula
For one dimension:
x_cm = (m₁x...
Showing 3 of 6 questions. Visit the full page for complete solutions.