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Power Play — Class 8 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 8 Mathematics chapter "Power Play" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 8 Mathematics chapter "Power Play" — 8 important questions with detailed answers for CBSE board exam prepa…

By Syllab.in · Updated Jun 14, 2026

Key Questions Covered:

  1. Simplify: 2⁵ × 2³
  2. Express 3⁻² in the form 1/aⁿ.
  3. Simplify: (5⁴/5²)
  4. Write 0.00001 in standard form (scientific notation).
  5. Simplify: (2³)² using the law of exponents.
  6. Write 725000 in standard form.
  7. + 2 more questions in the full chapter

Solutions Summary:

Question Status
Simplify: 2⁵ × 2³ ✓ Solved
Express 3⁻² in the form 1/aⁿ. ✓ Solved
Simplify: (5⁴/5²) ✓ Solved
Write 0.00001 in standard form (scientific notation). ✓ Solved
Simplify: (2³)² using the law of exponents. ✓ Solved
Write 725000 in standard form. ✓ Solved

Showing 6 of 8 questions

Q1: Simplify: 2⁵ × 2³

We need to multiply two powers with the same base. Step 1: Use the law of exponents: aᵐ × aⁿ = aᵐ⁺ⁿ Step 2: Apply the rule 2⁵ × 2³ = 2⁽⁵⁺³⁾ = 2⁸ Step 3: Calculate 2⁸ 2⁸ = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 Answer: 2⁵ × 2³ = 2⁸ = 256

Q2: Express 3⁻² in the form 1/aⁿ.

We need to convert a negative exponent to a positive form. Step 1: Use the law of exponents: a⁻ⁿ = 1/aⁿ Step 2: Apply the rule 3⁻² = 1/3² Step 3: Calculate 3² 3² = 3 × 3 = 9 Step 4: Final answer 3⁻² = 1/9 Answer: 3⁻² = 1/9

Q3: Simplify: (5⁴/5²)

We need to divide two powers with the same base. Step 1: Use the law of exponents: aᵐ/aⁿ = aᵐ⁻ⁿ (where m > n) Step 2: Apply the rule 5⁴/5² = 5⁽⁴⁻²⁾ = 5² Step 3: Calculate 5² 5² = 5 × 5 = 25 Answer: 5⁴/5² = 5² = 25

Q4: Write 0.00001 in standard form (scientific notation).

We need to express 0.00001 as a number between 1 and 10 multiplied by a power of 10. Step 1: Identify the non-zero digits 0.00001 has the digit 1 Step 2: Place the decimal point after the first non-zero digit 1.0 Step 3: Count how many places the decimal point moved Original: 0.00001 New position: 1.0 The decimal moved 5 places to the right. Step 4: When moving right, use negative exponent 0.00001 = 1 × 10⁻⁵ Step 5: Verify 1 × 10⁻⁵ = 1 × (1/100000) = 1/100000 = 0.00001 ✓ Answer: 0.00001 = ...

Q5: Simplify: (2³)² using the law of exponents.

We need to simplify a power raised to another power. Step 1: Use the law of exponents: (aᵐ)ⁿ = aᵐ×ⁿ Step 2: Apply the rule (2³)² = 2³×² = 2⁶ Step 3: Calculate 2⁶ 2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64 Step 4: Verify by calculating (2³)² directly (2³)² = (8)² = 8 × 8 = 64 ✓ Answer: (2³)² = 2⁶ = 64

Q6: Write 725000 in standard form.

We need to express 725000 as a number between 1 and 10 multiplied by a power of 10. Step 1: Identify where to place the decimal 725000 can be written as 725000.0 Step 2: Place the decimal after the first digit 7.25000 Step 3: Count how many places the decimal moved Original: 725000.0 (decimal at the end) New position: 7.25000 The decimal moved 5 places to the left. Step 4: When moving left, use positive exponent 725000 = 7.25 × 10⁵ Step 5: Verify 7.25 × 10⁵ = 7.25 × 100000 = 725000 ✓ Answe...

Showing 6 of 8 questions. Visit the full page for complete solutions.

More Class 8 Mathematics NCERT Solutions

  • A Square and a Cube — Class 8 Mathematics NCERT Solutions
  • A Story of Numbers — Class 8 Mathematics NCERT Solutions
  • Quadrilaterals — Class 8 Mathematics NCERT Solutions
  • Number Play — Class 8 Mathematics NCERT Solutions
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  • Proportional Reasoning 1 — Class 8 Mathematics NCERT Solutions
  • Fractions in Disguise — Class 8 Mathematics NCERT Solutions
  • The Baudhayana Pythagoras Theorem — Class 8 Mathematics NCERT Solutions
  • Proportional Reasoning 2 — Class 8 Mathematics NCERT Solutions
  • Exploring Some Geometric Themes — Class 8 Mathematics NCERT Solutions
  • Tales By Dots and Lines — Class 8 Mathematics NCERT Solutions
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