A Square and a Cube — Class 8 Mathematics NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 8 Mathematics chapter "A Square and a Cube" — 8 important questions with detailed answers for CBSE board exam preparation.
TL;DR: Free step-by-step NCERT solutions for Class 8 Mathematics chapter "A Square and a Cube" — 8 important questions with detailed answers for CBSE board e…
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Key Questions Covered:
- Find the square root of 256.
- Which of the following is a perfect square? 64, 100, 128, 150
- Find the cube root of 1000.
- Is 216 a perfect cube? Justify your answer.
- Find √(144/225).
- Find the smallest number by which 75 must be multiplied to make it a perfect …
- + 2 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| Find the square root of 256. | ✓ Solved |
| Which of the following is a perfect square? 64, 100, 128,… | ✓ Solved |
| Find the cube root of 1000. | ✓ Solved |
| Is 216 a perfect cube? Justify your answer. | ✓ Solved |
| Find √(144/225). | ✓ Solved |
| Find the smallest number by which 75 must be multiplied t… | ✓ Solved |
Showing 6 of 8 questions
Q1: Find the square root of 256.
We need to find a number that when multiplied by itself gives 256.
Step 1: Let √256 = x, so x² = 256
Step 2: We can find this by prime factorization.
256 = 2 × 128 = 2 × 2 × 64 = 2 × 2 × 2 × 32
= 2 × 2 × 2 × 2 × 16 = 2 × 2 × 2 × 2 × 2 × 8
= 2 × 2 × 2 × 2 × 2 × 2 × 4 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
= 2⁸
Step 3: √256 = √(2⁸) = 2⁴ = 16
Step 4: Verification: 16 × 16 = 256 ✓
Answer: √256 = 16
Q2: Which of the following is a perfect square? 64, 100, 128, 150
A perfect square is a number that can be expressed as the square of a whole number.
Step 1: Check 64
64 = 8 × 8 = 8²
✓ Perfect square
Step 2: Check 100
100 = 10 × 10 = 10²
✓ Perfect square
Step 3: Check 128
128 = 2 × 64 = 2 × 8²
This is not a perfect square because 128 = 2⁷, and the exponent is odd.
✗ Not a perfect square
Step 4: Check 150
150 = 2 × 75 = 2 × 3 × 25 = 2 × 3 × 5²
Since the exponents of 2 and 3 are odd, this is not a perfect square.
✗ Not a perfect square
Answer: 64 and 100 ar...
Q3: Find the cube root of 1000.
We need to find a number that when multiplied by itself three times gives 1000.
Step 1: Let ∛1000 = x, so x³ = 1000
Step 2: Prime factorization of 1000
1000 = 10 × 100 = 10 × 10 × 10 = 10³
or
1000 = 2 × 500 = 2 × 2 × 250 = 2 × 2 × 2 × 125
= 2³ × 125 = 2³ × 5³
Step 3: ∛1000 = ∛(10³) = 10
or
∛1000 = ∛(2³ × 5³) = ∛(2 × 5)³ = ∛(10³) = 10
Step 4: Verification: 10 × 10 × 10 = 1000 ✓
Answer: ∛1000 = 10
Q4: Is 216 a perfect cube? Justify your answer.
Step 1: Find the prime factorization of 216
216 = 2 × 108 = 2 × 2 × 54 = 2 × 2 × 2 × 27
= 2³ × 27 = 2³ × 3³
Step 2: Express as a product of prime factors
216 = 2³ × 3³ = (2 × 3)³ = 6³
Step 3: Check the exponents
For a number to be a perfect cube, all prime factors must have exponents divisible by 3.
Here, both 2 and 3 have exponent 3, which is divisible by 3.
Step 4: Verification: 6 × 6 × 6 = 36 × 6 = 216 ✓
Answer: Yes, 216 is a perfect cube because 216 = 6³
Q5: Find √(144/225).
We need to find the square root of a fraction.
Step 1: Use the property √(a/b) = √a/√b
√(144/225) = √144/√225
Step 2: Find √144
144 = 12 × 12 = 12²
√144 = 12
Step 3: Find √225
225 = 15 × 15 = 15²
√225 = 15
Step 4: Divide
√(144/225) = 12/15
Step 5: Simplify by finding GCD of 12 and 15
GCD(12, 15) = 3
12/15 = (12÷3)/(15÷3) = 4/5
Answer: √(144/225) = 4/5 or 0.8
Q6: Find the smallest number by which 75 must be multiplied to make it a perfect square.
Step 1: Find the prime factorization of 75
75 = 3 × 25 = 3 × 5²
Step 2: Analyze the exponents
For a perfect square, all prime factors must have even exponents.
- Prime factor 3 has exponent 1 (odd)
- Prime factor 5 has exponent 2 (even)
Step 3: Determine what to multiply
To make the exponent of 3 even, we need to multiply by 3 (to make it 3²).
The exponent of 5 is already even.
Step 4: The number to multiply is 3
75 × 3 = 225
Step 5: Verify that 225 is a perfect square
225 = 3² × 5² = (3 × 5...
Showing 6 of 8 questions. Visit the full page for complete solutions.
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