Wave Optics — Class 12 Physics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 12 Physics chapter "Wave Optics" — 7 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 12 Physics chapter "Wave Optics" — 7 important questions with detailed answers for CBSE board exam prepara…

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Key Questions Covered:

  1. Explain Huygens' principle and show how it accounts for reflection and refrac…
  2. What is interference? Derive the condition for constructive and destructive i…
  3. In Young's double slit experiment, the slits are 1 mm apart and screen is 1 m…
  4. + 4 more questions in the full chapter

Solutions Summary:

Question Status
Explain Huygens' principle and show how it accounts for r… ✓ Solved
What is interference? Derive the condition for constructi… ✓ Solved
In Young's double slit experiment, the slits are 1 mm apa… ✓ Solved

Showing 3 of 7 questions

Q1: Explain Huygens' principle and show how it accounts for reflection and refraction.

Huygens' Principle: Every point on a wavefront acts as a source of secondary wavelets, and the new wavefront is the envelope of these secondary wavelets. Reflection using Huygens' Principle: - Incident plane waves AB fall on plane surface MM' - Each point on AB generates secondary wavelets - At tim...

Q2: What is interference? Derive the condition for constructive and destructive interference in Young's double slit experiment.

Interference: Superposition of two coherent waves resulting in maximum or minimum intensity. Young's Double Slit Experiment: Two slits S₁ and S₂ separated by distance d Distance to screen: D >> d Wavelength: λ Path difference at point P on screen: Δ = S₂P - S₁P ≈ d sin θ ≈ d × y/D Where y = ...

Q3: In Young's double slit experiment, the slits are 1 mm apart and screen is 1 m away. Light of wavelength 500 nm is used. Find fringe width and position of 3rd bright fringe.

Given: Slit separation: d = 1 mm = 10⁻³ m Distance to screen: D = 1 m Wavelength: λ = 500 nm = 500 × 10⁻⁹ m = 5 × 10⁻⁷ m Fringe width: β = λD/d β = (5 × 10⁻⁷ × 1)/(10⁻³) β = 5 × 10⁻⁴ m = 0.5 mm Position of 3rd bright fringe (n = 3, counting from center at n = 0): For bright fringes: y_n = nλD/d Fo...

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