Ray Optics and Optical Instruments — Class 12 Physics NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 12 Physics chapter "Ray Optics and Optical Instruments" — 8 important questions with detailed answers for CBSE board exam preparation.
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TL;DR: Free step-by-step NCERT solutions for Class 12 Physics chapter "Ray Optics and Optical Instruments" — 8 important questions with detailed answers for…
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Key Questions Covered:
- What is refraction? State Snell's law and derive it using Huygens' principle.
- Define critical angle and total internal reflection. For glass (n = 1.5), fin…
- Derive lens maker's formula and show how it relates object distance, image di…
- An object 5 cm tall is placed 20 cm from a convex lens of focal length 10 cm.…
- What is power of a lens? A person has near point at 50 cm. What power of lens…
- Explain the construction and working of a microscope. Derive the magnifying p…
- + 2 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| What is refraction? State Snell's law and derive it using… | ✓ Solved |
| Define critical angle and total internal reflection. For … | ✓ Solved |
| Derive lens maker's formula and show how it relates objec… | ✓ Solved |
| An object 5 cm tall is placed 20 cm from a convex lens of… | ✓ Solved |
| What is power of a lens? A person has near point at 50 cm… | ✓ Solved |
| Explain the construction and working of a microscope. Der… | ✓ Solved |
Showing 6 of 8 questions
Q1: What is refraction? State Snell's law and derive it using Huygens' principle.
Refraction: Bending of light ray at the interface between two media of different optical densities.
Snell's Law: n₁ sin θ₁ = n₂ sin θ₂
Where n₁, n₂ are refractive indices; θ₁, θ₂ are angles of incidence and refraction.
Derivation using Huygens' Principle:
Consider plane wavefronts AB and A'B' incident on interface at angle θ₁.
Let speed of light: v₁ in medium 1, v₂ in medium 2
Time taken from B to B': t = BB'/v₁ = AB'/v₂
In triangle ABB':
BB' = AB' sin θ₁
In triangle AA'B':
AA' = AB' sin θ₂...
Q2: Define critical angle and total internal reflection. For glass (n = 1.5), find critical angle.
Critical Angle: Angle of incidence in denser medium for which angle of refraction is 90°.
Total Internal Reflection: Complete reflection of light at interface from denser to rarer medium when angle of incidence exceeds critical angle.
Derivation:
At critical angle θ_c, refraction angle = 90°
Using Snell's law: n₁ sin θ_c = n₂ sin 90°
n₁ sin θ_c = n₂ × 1
sin θ_c = n₂/n₁ = 1/n (for denser to rarer medium)
θ_c = sin⁻¹(1/n)
For glass-air interface (n = 1.5):
sin θ_c = 1/1.5 = 2/3
θ_c = sin⁻¹(0.66...
Q3: Derive lens maker's formula and show how it relates object distance, image distance, and focal length.
Lens Maker's Formula: 1/f = (n - 1)[1/R₁ - 1/R₂]
Where n = refractive index, R₁, R₂ = radii of curvature
Derivation:
Consider a thin lens with radii R₁ (first surface) and R₂ (second surface).
For refraction at first surface (air to glass):
1/s₁ + n/s₁' = (n-1)/R₁
For refraction at second surface (glass to air):
n/(-s₁' + t) + 1/s₂' = (1-n)/R₂
For thin lens, t → 0:
n/(-s₁') + 1/s₂' = (1-n)/R₂
Using object distance s = s₁ and image distance s' = s₂':
1/s + 1/s' = (n-1)[1/R₁ - 1/R₂]
Lens Equ...
Q4: An object 5 cm tall is placed 20 cm from a convex lens of focal length 10 cm. Find image position, size, and nature.
Given:
Object height h₁ = 5 cm
Object distance u = 20 cm
Focal length f = 10 cm (convex lens)
Using lens equation: 1/f = 1/u + 1/v
1/10 = 1/20 + 1/v
1/v = 1/10 - 1/20 = 2/20 - 1/20 = 1/20
v = 20 cm
Image is at 20 cm from lens (on opposite side of object)
Magnification: m = -v/u = -20/20 = -1
Image height: h₂ = m × h₁ = (-1) × 5 = -5 cm
(Negative sign indicates inverted image)
Nature of image:
- Real image (v > 0)
- Inverted (m < 0)
- Same size as object (|m| = 1)
- At 2f position (u =...
Q5: What is power of a lens? A person has near point at 50 cm. What power of lens is required to correct this vision defect?
Power of Lens: Reciprocal of focal length in meters.
P = 1/f (in diopters, D)
f in meters
Vision Defect: Hypermetropia (far-sightedness)
Near point at 50 cm instead of normal 25 cm
Correction Required:
For comfortable reading at D = 25 cm (normal near point), the lens should form virtual image at 50 cm when object is at 25 cm.
Using lens equation: 1/f = 1/u + 1/v
Here: u = 25 cm = 0.25 m, v = -50 cm = -0.5 m (virtual image, negative)
1/f = 1/0.25 + 1/(-0.5)
1/f = 4 - 2 = 2
f = 0.5 m = +50 cm...
Q6: Explain the construction and working of a microscope. Derive the magnifying power.
Microscope: Optical instrument for viewing small objects magnified.
Construction:
- Objective lens: small focal length (f_o ≈ 1-5 mm), high power
- Eyepiece (ocular): moderate focal length (f_e ≈ 2-3 cm), acts as magnifying glass
- Tube length: distance between focal points of objective and eyepiece
- Lenses placed close together: separation ≈ L (tube length)
Working:
1. Object placed just beyond focal point of objective
2. Objective forms real, magnified, inverted image
3. This image acts as ...
Showing 6 of 8 questions. Visit the full page for complete solutions.
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