Electromagnetic Induction — Class 12 Physics NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 12 Physics chapter "Electromagnetic Induction" — 7 important questions with detailed answers for CBSE board exam preparation.
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TL;DR: Free step-by-step NCERT solutions for Class 12 Physics chapter "Electromagnetic Induction" — 7 important questions with detailed answers for CBSE boar…
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Key Questions Covered:
- State Faraday's law of electromagnetic induction. Write mathematical expression.
- A square loop of side 10 cm is placed in magnetic field 0.5 T. If field decre…
- Define self-inductance (L). Derive expression for self-inductance of solenoid.
- What is mutual inductance (M)? Explain with two coils.
- Define AC generator. Derive expression for induced emf in rotating rectangula…
- A rectangular coil of 100 turns, area 0.05 m², rotates in magnetic field of 0…
- + 1 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| State Faraday's law of electromagnetic induction. Write m… | ✓ Solved |
| A square loop of side 10 cm is placed in magnetic field 0… | ✓ Solved |
| Define self-inductance (L). Derive expression for self-in… | ✓ Solved |
| What is mutual inductance (M)? Explain with two coils. | ✓ Solved |
| Define AC generator. Derive expression for induced emf in… | ✓ Solved |
| A rectangular coil of 100 turns, area 0.05 m², rotates in… | ✓ Solved |
Showing 6 of 7 questions
Q1: State Faraday's law of electromagnetic induction. Write mathematical expression.
Faraday's Law of Electromagnetic Induction: Rate of change of magnetic flux through a circuit induces emf in the circuit.
Mathematical Expression:
ε = -dΦ_B/dt
where ε = induced emf (volts)
Φ_B = magnetic flux (Weber, Wb)
t = time (seconds)
Alternatively, for N turns:
ε = -N(dΦ_B/dt)
Integral form over time interval t₁ to t₂:
ε = -N × (Φ₂ - Φ₁)/(t₂ - t₁)
Magnetic Flux:
Φ_B = ∫B⋅dA = BA cos θ (for uniform field)
where B = magnetic flux density
A = area of loop
θ = angle between B and normal...
Q2: A square loop of side 10 cm is placed in magnetic field 0.5 T. If field decreases to 0.2 T in 0.1 s, find induced emf.
Given: Side of square loop = 10 cm = 0.1 m
Initial magnetic field B₁ = 0.5 T
Final magnetic field B₂ = 0.2 T
Time interval Δt = 0.1 s
Field perpendicular to loop (θ = 0°)
Area of loop:
A = side² = (0.1)² = 0.01 m²
Initial flux:
Φ₁ = B₁A cos 0° = 0.5 × 0.01 = 0.005 Wb
Final flux:
Φ₂ = B₂A cos 0° = 0.2 × 0.01 = 0.002 Wb
Change in flux:
ΔΦ = Φ₂ - Φ₁ = 0.002 - 0.005 = -0.003 Wb
Rate of change of flux:
dΦ/dt = ΔΦ/Δt = -0.003 / 0.1 = -0.03 Wb/s
Induced emf (using Faraday's law):
ε = -dΦ/dt = -(-...
Q3: Define self-inductance (L). Derive expression for self-inductance of solenoid.
Self-Inductance (L): Property of coil to oppose change in its own current.
Definition: L = |ε|/|dI/dt| = Φ_B/I
where ε = induced emf
dI/dt = rate of change of current
Φ_B = magnetic flux through coil
I = current in coil
SI Unit: Henry (H) = Wb/A = V⋅s/A
Smaller units: mH (millihenry), μH (microhenry)
For Solenoid:
Consider solenoid with N turns, length L, cross-sectional area A.
Magnetic field inside solenoid:
B = μ₀nI = μ₀(N/L)I
Magnetic flux through each turn:
Φ = BA = μ₀(N/L) × I × A
...
Q4: What is mutual inductance (M)? Explain with two coils.
Mutual Inductance (M): Property describing how change in current in one coil induces emf in nearby coil.
Definition:
M₁₂ = Φ₂₁/I₁ = |ε₂|/|dI₁/dt|
where Φ₂₁ = flux through coil 2 due to current I₁ in coil 1
ε₂ = induced emf in coil 2
I₁ = current in coil 1
SI Unit: Henry (H)
For two coils:
Coil 1 (primary): Current I₁, N₁ turns, area A₁
Coil 2 (secondary): N₂ turns, area A₂, separation d
Mutual inductance:
M₁₂ = M₂₁ = M (reciprocal property)
Expression (ideal case, coils wound on same core)...
Q5: Define AC generator. Derive expression for induced emf in rotating rectangular coil.
AC Generator: Device that converts mechanical energy into electrical energy using electromagnetic induction.
Principle: Rotating coil in uniform magnetic field generates alternating emf.
Derivation for Rectangular Coil:
Setup:
- Rectangular coil with N turns, area A
- Rotates in uniform magnetic field B
- Angular velocity ω (rad/s)
- At t = 0, coil plane parallel to field (flux = 0)
Step 1: Angle θ between normal and field at time t
θ = ωt (starting from θ = 0)
Step 2: Magnetic flux through...
Q6: A rectangular coil of 100 turns, area 0.05 m², rotates in magnetic field of 0.2 T at 50 Hz. Find peak and RMS values of induced emf.
Given: N = 100 turns
A = 0.05 m²
B = 0.2 T
f = 50 Hz (frequency)
Angular velocity:
ω = 2πf = 2π × 50 = 100π rad/s
Peak (Maximum) EMF:
ε₀ = NBAω
Step 1: ε₀ = 100 × 0.2 × 0.05 × 100π
Step 2: ε₀ = 100 × 0.2 × 0.05 × 100π
Step 3: ε₀ = 100 × 1 × π = 100π V
Step 4: ε₀ = 314.16 V ≈ 314 V
RMS Value:
ε_rms = ε₀/√2
Step 1: ε_rms = 100π/√2
Step 2: ε_rms = 100π/1.414
Step 3: ε_rms = 314.16/1.414
Step 4: ε_rms = 222.14 V ≈ 222 V
Alternatively:
ε_rms = 2πfNBA/√2 = (2π × 50 × 100 × 0.2 × 0.05)/√2
ε_rms =...
Showing 6 of 7 questions. Visit the full page for complete solutions.
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