Journey Inside the Atom — Class 9 Science NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 9 Science chapter "Journey Inside the Atom" — 8 important questions with detailed answers for CBSE board exam preparation.
✓ 100% Free
✓ No Login Needed
✓ NCERT / CBSE Aligned
✓ Download as PDF
TL;DR: Free step-by-step NCERT solutions for Class 9 Science chapter "Journey Inside the Atom" — 8 important questions with detailed answers for CBSE board e…
Written & reviewed by the Syllab.in Academic Team (CBSE/NCERT subject experts) · Updated
🤖 Stuck on any question? Ask Syllab's free AI Tutor for a step-by-step explanation — instant, unlimited, no login.
Key Questions Covered:
- What are the three subatomic particles and their charges?
- State and explain Thomson's model of atom.
- What are the main features of Rutherford's model of atom?
- Explain Bohr's model of atom. Why is it better than Rutherford's?
- Define atomic number and mass number. How are they related?
- What is valency? How does electron configuration determine valency?
- + 2 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| What are the three subatomic particles and their charges? | ✓ Solved |
| State and explain Thomson's model of atom. | ✓ Solved |
| What are the main features of Rutherford's model of atom? | ✓ Solved |
| Explain Bohr's model of atom. Why is it better than Ruthe… | ✓ Solved |
| Define atomic number and mass number. How are they related? | ✓ Solved |
| What is valency? How does electron configuration determin… | ✓ Solved |
Showing 6 of 8 questions
Q1: What are the three subatomic particles and their charges?
The three subatomic particles are:
(1) Electron — negatively charged (charge = -1), mass = 1/1836 amu, found in orbitals around nucleus
(2) Proton — positively charged (charge = +1), mass = 1 amu, present in nucleus
(3) Neutron — neutral (charge = 0), mass ≈ 1 amu, present in nucleus
Q2: State and explain Thomson's model of atom.
Thomson's model (plum pudding model):
Atom is a sphere of positive charge with electrons embedded in it like raisins in a pudding.
Characteristics: (1) Positive charge uniformly distributed throughout atom
(2) Electrons scattered throughout in this positive charge
(3) Atom is electrically neutral
Limitations: Could not explain scattering of α-particles; disproved by Rutherford's experiments.
Q3: What are the main features of Rutherford's model of atom?
Rutherford's nuclear model:
(1) Atom has a small, dense, positively charged nucleus at center
(2) Electrons revolve around nucleus in circular paths
(3) Most of atom's mass is concentrated in nucleus
(4) Nucleus contains protons; electrons in orbits
(5) Atom is mostly empty space
Limitation: Could not explain stability of electrons; they should spiral into nucleus.
Q4: Explain Bohr's model of atom. Why is it better than Rutherford's?
Bohr's model:
(1) Electrons exist in fixed orbits/shells (n = 1, 2, 3...) at specific distances from nucleus
(2) Electrons in a shell have definite energy; transition between shells requires energy
(3) Orbits are labeled K, L, M, N (n = 1, 2, 3, 4...)
(4) Maximum electrons in shell = 2n²
Advantages over Rutherford: (1) Explains why electrons don't spiral into nucleus
(2) Explains discrete energy levels and spectral lines
(3) Applies to hydrogen and hydrogen-like atoms
Q5: Define atomic number and mass number. How are they related?
Atomic number (Z) = Number of protons in nucleus = Number of electrons in neutral atom
Mass number (A) = Total number of protons + neutrons = Z + N
where N = number of neutrons
Example: ₁₆³²S has Z = 16 (16 protons), A = 32, so N = 32 - 16 = 16 neutrons
Atomic number determines element identity; mass number determines isotope.
Q6: What is valency? How does electron configuration determine valency?
Valency = Number of electrons lost, gained, or shared by atom to achieve stable octet (8 electrons in outermost shell) or duplet (2 electrons for H, He).
Rules: (1) If valence electrons < 4: valency = number of valence electrons
(2) If valence electrons ≥ 4: valency = 8 - number of valence electrons
Example: Chlor (17e⁻): 2, 8, 7 → 7 valence electrons → valency = 8 - 7 = 1
Oxygen (8e⁻): 2, 6 → 6 valence electrons → valency = 8 - 6 = 2
Showing 6 of 8 questions. Visit the full page for complete solutions.
More Class 9 Science NCERT Solutions
- Cell the Building Block of Life — Class 9 Science NCERT Solutions
- Tissues in Action — Class 9 Science NCERT Solutions
- Describing Motion Around Us — Class 9 Science NCERT Solutions
- Exploring Mixtures and Their Separation — Class 9 Science NCERT Solutions
- How Forces Affect Motion — Class 9 Science NCERT Solutions
- Work Energy and Simple Machines — Class 9 Science NCERT Solutions
- Atomic Foundations of Matter — Class 9 Science NCERT Solutions
- Sound Waves Characteristics and Applications — Class 9 Science NCERT Solutions
- Reproduction How Life Continues — Class 9 Science NCERT Solutions
- Patterns in Life Diversity and Classification — Class 9 Science NCERT Solutions
- Earth As a System Energy Matter and Life — Class 9 Science NCERT Solutions
- Matter Exemplar — Class 9 Science NCERT Solutions
- Atoms Molecules Exemplar — Class 9 Science NCERT Solutions
- Motion Exemplar — Class 9 Science NCERT Solutions
- Gravitation Exemplar — Class 9 Science NCERT Solutions