Gravitation Exemplar — Class 9 Science NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 9 Science chapter "Gravitation Exemplar" — 5 important questions with detailed answers for CBSE board exam preparation.
TL;DR: Free step-by-step NCERT solutions for Class 9 Science chapter "Gravitation Exemplar" — 5 important questions with detailed answers for CBSE board exam…
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Key Questions Covered:
- Calculate the gravitational force between two masses 5 kg and 10 kg separated…
- Why is the weight of an object less on the moon than on Earth?
- A body weighs 50 N on Earth. What is its mass? (g = 10 m/s²)
- State the universal law of gravitation.
- If Earth's mass is 6 × 10^24 kg and radius is 6.4 × 10^6 m, calculate g at Ea…
Solutions Summary:
| Question | Status |
|---|---|
| Calculate the gravitational force between two masses 5 kg… | ✓ Solved |
| Why is the weight of an object less on the moon than on E… | ✓ Solved |
| A body weighs 50 N on Earth. What is its mass? (g = 10 m/s²) | ✓ Solved |
| State the universal law of gravitation. | ✓ Solved |
| If Earth's mass is 6 × 10^24 kg and radius is 6.4 × 10^6 … | ✓ Solved |
Showing 5 of 5 questions
Q1: Calculate the gravitational force between two masses 5 kg and 10 kg separated by 2 m. (G = 6.67 × 10^-11 N·m²/kg²)
F = G(m1 × m2)/r² = (6.67 × 10^-11)(5)(10)/(4) = (6.67 × 10^-11)(50/4) = 8.34 × 10^-10 N.
Q2: Why is the weight of an object less on the moon than on Earth?
Weight is W = mg, where g depends on mass and radius of celestial body: g = GM/R². Moon has smaller mass and radius than Earth, so g_moon = 1.6 m/s² while g_earth = 10 m/s². Thus weight on moon is 1/6 of weight on Earth.
Q3: A body weighs 50 N on Earth. What is its mass? (g = 10 m/s²)
Weight W = mg. So m = W/g = 50/10 = 5 kg. The mass remains 5 kg anywhere (on Earth, moon, space).
Q4: State the universal law of gravitation.
Every object attracts every other object with force proportional to product of their masses and inversely proportional to square of distance between them. Mathematically: F = G(m1 × m2)/r², where G is gravitational constant.
Q5: If Earth's mass is 6 × 10^24 kg and radius is 6.4 × 10^6 m, calculate g at Earth's surface.
g = GM/R² = (6.67 × 10^-11)(6 × 10^24)/(6.4 × 10^6)² = (40 × 10^13)/(41 × 10^12) ≈ 9.76 m/s² ≈ 10 m/s².
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