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Number Play — Class 7 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 7 Mathematics chapter "Number Play" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 7 Mathematics chapter "Number Play" — 8 important questions with detailed answers for CBSE board exam prep…

By Syllab.in · Updated Jun 14, 2026

Key Questions Covered:

  1. Find the next three numbers in the pattern: 2, 6, 18, 54, ...
  2. Check if 256 is divisible by 8 without performing division.
  3. Is 4527 divisible by 3? Use the divisibility rule.
  4. Find HCF (Highest Common Factor) of 24 and 36 using the Euclidean algorithm.
  5. Check if 144 is a perfect square. If yes, find its square root.
  6. Find the LCM (Least Common Multiple) of 12 and 18.
  7. + 2 more questions in the full chapter

Solutions Summary:

Question Status
Find the next three numbers in the pattern: 2, 6, 18, 54,… ✓ Solved
Check if 256 is divisible by 8 without performing division. ✓ Solved
Is 4527 divisible by 3? Use the divisibility rule. ✓ Solved
Find HCF (Highest Common Factor) of 24 and 36 using the E… ✓ Solved
Check if 144 is a perfect square. If yes, find its square… ✓ Solved
Find the LCM (Least Common Multiple) of 12 and 18. ✓ Solved

Showing 6 of 8 questions

Q1: Find the next three numbers in the pattern: 2, 6, 18, 54, ...

Step 1: Identify the pattern by finding the relationship between consecutive terms: 6 ÷ 2 = 3 18 ÷ 6 = 3 54 ÷ 18 = 3 Step 2: The pattern multiplies by 3 each time (geometric progression with ratio 3). Step 3: Find next three terms: Next term: 54 × 3 = 162 Next term: 162 × 3 = 486 Next term: 486 × 3 = 1458 Answer: 162, 486, 1458

Q2: Check if 256 is divisible by 8 without performing division.

Step 1: Apply divisibility rule for 8: A number is divisible by 8 if its last three digits are divisible by 8. Step 2: Last three digits of 256 are: 256 Step 3: Check if 256 is divisible by 8: 256 ÷ 8 = 32 (exactly) So yes, 256 is divisible by 8. Step 4: Verify using the rule: 256 = 200 + 56 We need to check just 256. 8 × 32 = 256 ✓ Answer: Yes, 256 is divisible by 8.

Q3: Is 4527 divisible by 3? Use the divisibility rule.

Step 1: Divisibility rule for 3: A number is divisible by 3 if the sum of its digits is divisible by 3. Step 2: Find sum of digits of 4527: 4 + 5 + 2 + 7 = 18 Step 3: Check if 18 is divisible by 3: 18 ÷ 3 = 6 (exactly) Yes, 18 is divisible by 3. Step 4: Therefore, 4527 is divisible by 3. Verify: 4527 ÷ 3 = 1509 ✓ Answer: Yes, 4527 is divisible by 3 (since sum of digits = 18, which is divisible by 3).

Q4: Find HCF (Highest Common Factor) of 24 and 36 using the Euclidean algorithm.

Step 1: Apply Euclidean algorithm (repeated division): 36 = 24 × 1 + 12 Step 2: Replace larger number with divisor, divisor with remainder: 24 = 12 × 2 + 0 Step 3: When remainder is 0, the divisor is the HCF: HCF(24, 36) = 12 Step 4: Verify by listing factors: Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24 Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 Common factors: 1, 2, 3, 4, 6, 12 Highest common factor: 12 ✓ Answer: HCF(24, 36) = 12

Q5: Check if 144 is a perfect square. If yes, find its square root.

Step 1: A perfect square is a number that can be expressed as the product of an integer with itself. Step 2: Try to find the square root: √144 = ? We need to find a number that when multiplied by itself gives 144. Step 3: Check: 12 × 12 = 144 ✓ Step 4: Therefore, 144 is a perfect square. √144 = 12 Answer: Yes, 144 is a perfect square. √144 = 12

Q6: Find the LCM (Least Common Multiple) of 12 and 18.

Step 1: Find the prime factorization of each number: 12 = 2² × 3 18 = 2 × 3² Step 2: LCM is the product of highest powers of all prime factors: Highest power of 2: 2² Highest power of 3: 3² Step 3: Calculate LCM: LCM(12, 18) = 2² × 3² = 4 × 9 = 36 Step 4: Verify: 12 × 3 = 36 ✓ (36 is a multiple of 12) 18 × 2 = 36 ✓ (36 is a multiple of 18) Answer: LCM(12, 18) = 36

Showing 6 of 8 questions. Visit the full page for complete solutions.

More Class 7 Mathematics NCERT Solutions

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  • Operations with Integers — Class 7 Mathematics NCERT Solutions
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  • Another Peek Beyond the Point — Class 7 Mathematics NCERT Solutions
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