Number Play — Class 7 Mathematics NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 7 Mathematics chapter "Number Play" — 8 important questions with detailed answers for CBSE board exam preparation.
TL;DR: Free step-by-step NCERT solutions for Class 7 Mathematics chapter "Number Play" — 8 important questions with detailed answers for CBSE board exam prep…
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Key Questions Covered:
- Find the next three numbers in the pattern: 2, 6, 18, 54, ...
- Check if 256 is divisible by 8 without performing division.
- Is 4527 divisible by 3? Use the divisibility rule.
- Find HCF (Highest Common Factor) of 24 and 36 using the Euclidean algorithm.
- Check if 144 is a perfect square. If yes, find its square root.
- Find the LCM (Least Common Multiple) of 12 and 18.
- + 2 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| Find the next three numbers in the pattern: 2, 6, 18, 54,… | ✓ Solved |
| Check if 256 is divisible by 8 without performing division. | ✓ Solved |
| Is 4527 divisible by 3? Use the divisibility rule. | ✓ Solved |
| Find HCF (Highest Common Factor) of 24 and 36 using the E… | ✓ Solved |
| Check if 144 is a perfect square. If yes, find its square… | ✓ Solved |
| Find the LCM (Least Common Multiple) of 12 and 18. | ✓ Solved |
Showing 6 of 8 questions
Q1: Find the next three numbers in the pattern: 2, 6, 18, 54, ...
Step 1: Identify the pattern by finding the relationship between consecutive terms:
6 ÷ 2 = 3
18 ÷ 6 = 3
54 ÷ 18 = 3
Step 2: The pattern multiplies by 3 each time (geometric progression with ratio 3).
Step 3: Find next three terms:
Next term: 54 × 3 = 162
Next term: 162 × 3 = 486
Next term: 486 × 3 = 1458
Answer: 162, 486, 1458
Q2: Check if 256 is divisible by 8 without performing division.
Step 1: Apply divisibility rule for 8:
A number is divisible by 8 if its last three digits are divisible by 8.
Step 2: Last three digits of 256 are: 256
Step 3: Check if 256 is divisible by 8:
256 ÷ 8 = 32 (exactly)
So yes, 256 is divisible by 8.
Step 4: Verify using the rule:
256 = 200 + 56
We need to check just 256.
8 × 32 = 256 ✓
Answer: Yes, 256 is divisible by 8.
Q3: Is 4527 divisible by 3? Use the divisibility rule.
Step 1: Divisibility rule for 3:
A number is divisible by 3 if the sum of its digits is divisible by 3.
Step 2: Find sum of digits of 4527:
4 + 5 + 2 + 7 = 18
Step 3: Check if 18 is divisible by 3:
18 ÷ 3 = 6 (exactly)
Yes, 18 is divisible by 3.
Step 4: Therefore, 4527 is divisible by 3.
Verify: 4527 ÷ 3 = 1509 ✓
Answer: Yes, 4527 is divisible by 3 (since sum of digits = 18, which is divisible by 3).
Q4: Find HCF (Highest Common Factor) of 24 and 36 using the Euclidean algorithm.
Step 1: Apply Euclidean algorithm (repeated division):
36 = 24 × 1 + 12
Step 2: Replace larger number with divisor, divisor with remainder:
24 = 12 × 2 + 0
Step 3: When remainder is 0, the divisor is the HCF:
HCF(24, 36) = 12
Step 4: Verify by listing factors:
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
Common factors: 1, 2, 3, 4, 6, 12
Highest common factor: 12 ✓
Answer: HCF(24, 36) = 12
Q5: Check if 144 is a perfect square. If yes, find its square root.
Step 1: A perfect square is a number that can be expressed as the product of an integer with itself.
Step 2: Try to find the square root:
√144 = ?
We need to find a number that when multiplied by itself gives 144.
Step 3: Check:
12 × 12 = 144 ✓
Step 4: Therefore, 144 is a perfect square.
√144 = 12
Answer: Yes, 144 is a perfect square. √144 = 12
Q6: Find the LCM (Least Common Multiple) of 12 and 18.
Step 1: Find the prime factorization of each number:
12 = 2² × 3
18 = 2 × 3²
Step 2: LCM is the product of highest powers of all prime factors:
Highest power of 2: 2²
Highest power of 3: 3²
Step 3: Calculate LCM:
LCM(12, 18) = 2² × 3² = 4 × 9 = 36
Step 4: Verify:
12 × 3 = 36 ✓ (36 is a multiple of 12)
18 × 2 = 36 ✓ (36 is a multiple of 18)
Answer: LCM(12, 18) = 36
Showing 6 of 8 questions. Visit the full page for complete solutions.
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