Vector Algebra — Class 12 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 12 Mathematics chapter "Vector Algebra" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 12 Mathematics chapter "Vector Algebra" — 8 important questions with detailed answers for CBSE board exam…

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Key Questions Covered:

  1. Find the magnitude of the vector a = 3î + 4ĵ.
  2. Find the dot product of vectors a = 2î + 3ĵ + k̂ and b = î + 2ĵ - k̂.
  3. Find the cross product a × b where a = î + 2ĵ + 3k̂ and b = 2î + 3ĵ + k̂.
  4. + 5 more questions in the full chapter

Solutions Summary:

Question Status
Find the magnitude of the vector a = 3î + 4ĵ. ✓ Solved
Find the dot product of vectors a = 2î + 3ĵ + k̂ and b = … ✓ Solved
Find the cross product a × b where a = î + 2ĵ + 3k̂ and b… ✓ Solved

Showing 3 of 8 questions

Q1: Find the magnitude of the vector a = 3î + 4ĵ.

To find the magnitude of a = 3î + 4ĵ: Step 1: Use the magnitude formula. For a vector a = xî + yĵ + zk̂, |a| = √(x² + y² + z²) Step 2: Identify components. Here: x = 3, y = 4, z = 0 Step 3: Calculate. |a| = √(3² + 4² + 0²) = √(9 + 16) = √25 = 5 Final Answer: |a| = 5 units

Q2: Find the dot product of vectors a = 2î + 3ĵ + k̂ and b = î + 2ĵ - k̂.

To find a · b where a = 2î + 3ĵ + k̂ and b = î + 2ĵ - k̂: Step 1: Use dot product formula. a · b = (a₁î + a₂ĵ + a₃k̂) · (b₁î + b₂ĵ + b₃k̂) = a₁b₁ + a₂b₂ + a₃b₃ Step 2: Identify components. a₁ = 2, a₂ = 3, a₃ = 1 b₁ = 1, b₂ = 2, b₃ = -1 Step 3: Calculate. a · b = (2)(1) + (3)(2) + (1)(-1) = 2 + 6 ...

Q3: Find the cross product a × b where a = î + 2ĵ + 3k̂ and b = 2î + 3ĵ + k̂.

To find a × b where a = î + 2ĵ + 3k̂ and b = 2î + 3ĵ + k̂: Step 1: Use the determinant formula. a × b = |î ĵ k̂ | |1 2 3 | |2 3 1 | Step 2: Expand the determinant. a × b = î(2×1 - 3×3) - ĵ(1×1 - 3×2) + k̂(1×3 - 2×2) = î(2 - 9) - ĵ(1 - 6) + k̂(3 - 4) = î(-7) - ĵ...

Showing 3 of 8 questions. Visit the full page for complete solutions.