Probability — Class 12 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 12 Mathematics chapter "Probability" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 12 Mathematics chapter "Probability" — 8 important questions with detailed answers for CBSE board exam pre…

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Key Questions Covered:

  1. Two dice are thrown simultaneously. Find the probability of getting a sum of 7.
  2. A card is drawn from a standard deck of 52 cards. Find the probability that i…
  3. In a class of 30 students, 18 study Mathematics, 12 study Physics, and 8 stud…
  4. + 5 more questions in the full chapter

Solutions Summary:

Question Status
Two dice are thrown simultaneously. Find the probability … ✓ Solved
A card is drawn from a standard deck of 52 cards. Find th… ✓ Solved
In a class of 30 students, 18 study Mathematics, 12 study… ✓ Solved

Showing 3 of 8 questions

Q1: Two dice are thrown simultaneously. Find the probability of getting a sum of 7.

To find P(sum = 7): Step 1: Find total possible outcomes. When two dice are thrown: 6 × 6 = 36 outcomes Step 2: Find favorable outcomes (sum = 7). List all pairs (a, b) where a + b = 7: (1, 6): 1 + 6 = 7 (2, 5): 2 + 5 = 7 (3, 4): 3 + 4 = 7 (4, 3): 4 + 3 = 7 (5, 2): 5 + 2 = 7 (6, 1): 6 + 1 = 7 Num...

Q2: A card is drawn from a standard deck of 52 cards. Find the probability that it is a red card or a king.

To find P(red card OR king): Step 1: Identify the events. Event A: Card is red Event B: Card is a king Step 2: Count favorable outcomes. Red cards: 26 (13 hearts + 13 diamonds) Kings: 4 (one in each suit) Red kings: 2 (king of hearts and king of diamonds) Step 3: Use inclusion-exclusion principle...

Q3: In a class of 30 students, 18 study Mathematics, 12 study Physics, and 8 study both. If a student is selected at random, find the probability that the student studies either Mathematics or Physics.

To find P(Mathematics OR Physics): Step 1: Identify given information. n(M) = 18 (students studying Mathematics) n(P) = 12 (students studying Physics) n(M ∩ P) = 8 (students studying both) n(Total) = 30 Step 2: Use inclusion-exclusion principle. n(M ∪ P) = n(M) + n(P) - n(M ∩ P) = 18 + 12 - 8 = 22...

Showing 3 of 8 questions. Visit the full page for complete solutions.