Solutions — Class 12 Chemistry NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Solutions" — 8 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Solutions" — 8 important questions with detailed answers for CBSE board exam prepara…

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Key Questions Covered:

  1. Define a solution. What are the main components of a solution?
  2. Calculate the molarity of a solution containing 10.6 g of Na₂CO₃ dissolved in…
  3. What is the difference between molarity and molality?
  4. + 5 more questions in the full chapter

Solutions Summary:

Question Status
Define a solution. What are the main components of a solu… ✓ Solved
Calculate the molarity of a solution containing 10.6 g of… ✓ Solved
What is the difference between molarity and molality? ✓ Solved

Showing 3 of 8 questions

Q1: Define a solution. What are the main components of a solution?

A solution is a homogeneous mixture of two or more substances where one substance (solute) is uniformly dispersed in another (solvent). Main components: 1. Solvent: The substance in which solute dissolves (usually present in larger amount). Typically liquid. 2. Solute: The substance being dissolved...

Q2: Calculate the molarity of a solution containing 10.6 g of Na₂CO₃ dissolved in water to make 500 mL of solution.

Given: Mass of Na₂CO₃ = 10.6 g, Volume of solution = 500 mL = 0.5 L Step 1: Calculate molar mass of Na₂CO₃ Molar mass = (2 × 23) + 12 + (3 × 16) = 46 + 12 + 48 = 106 g/mol Step 2: Calculate number of moles Moles = mass / molar mass = 10.6 / 106 = 0.1 mol Step 3: Calculate molarity Molarity = mole...

Q3: What is the difference between molarity and molality?

Molarity (M): 1. Defined as moles of solute per litre of solution 2. Formula: M = moles / volume of solution (L) 3. Temperature dependent (volume changes with temperature) 4. Used in laboratory work and dilution calculations Molality (m): 1. Defined as moles of solute per kilogram of solvent 2. For...

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