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Amines — Class 12 Chemistry NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Amines" — 7 important questions with detailed answers for CBSE board exam preparation.

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TL;DR: Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Amines" — 7 important questions with detailed answers for CBSE board exam preparatio…

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Key Questions Covered:

  1. Define amines. What is the difference between primary, secondary, and tertiar…
  2. Explain the basicity of amines. Why are amines basic in character? Compare th…
  3. Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its structure and classify …
  4. Describe the reaction of amines with acids. Write the equation for the reacti…
  5. Explain the Hofmann elimination reaction. Write the equation for the Hofmann …
  6. What happens when aniline is treated with nitrous acid at 0°C? Write the equa…
  7. + 1 more questions in the full chapter

Solutions Summary:

Question Status
Define amines. What is the difference between primary, se… ✓ Solved
Explain the basicity of amines. Why are amines basic in c… ✓ Solved
Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its str… ✓ Solved
Describe the reaction of amines with acids. Write the equ… ✓ Solved
Explain the Hofmann elimination reaction. Write the equat… ✓ Solved
What happens when aniline is treated with nitrous acid at… ✓ Solved

Showing 6 of 7 questions

Q1: Define amines. What is the difference between primary, secondary, and tertiary amines? Give one example of each.

Amines: Organic compounds derived from ammonia (NH3) by replacement of one, two, or three hydrogen atoms with alkyl or aryl groups. General formula: R-NH2, R2N-H, or R3N Classification: Primary amines (1° amine): - One hydrogen of ammonia is replaced by an alkyl or aryl group - General formula: R-NH2 - Contains one N-H bond and one N-C bond - Example: CH3CH2NH2 (ethylamine or ethanamine) - Structure: C-NH2 Secondary amines (2° amine): - Two hydrogens of ammonia are replaced by alkyl or aryl ...

Q2: Explain the basicity of amines. Why are amines basic in character? Compare the basicity of primary, secondary, and tertiary amines.

Basicity of amines: Amines are basic because they contain a lone pair of electrons on the nitrogen atom. This lone pair can accept a proton (H+) from an acid. General reaction: R-NH2 + HX → R-NH3+ + X- (or R-NH3+X-) The amine acts as a proton acceptor (Lewis base): R-NH2 + H+ → R-NH3+ Basic strength comparison: Primary (RNH2) > Tertiary (R3N) > Secondary (R2NH) Detailed explanation: 1. Basicity order and reasons: - Primary amines: Strongest (in aliphatic series) - Tertiary ami...

Q3: Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its structure and classify this amine.

Structure of (CH3)2N-CH2-CH3: CH3 | CH3-N-CH2-CH3 | CH3 Alternative representation: CH3-N(CH3)-CH2-CH3 IUPAC name: N,N-dimethylethanamine Naming explanation: 1. Main chain: ethane (2 carbons attached to N in the longest chain) 2. Functional group: amine (-amine suffix) 3. The nitrogen is attached to: - Two methyl groups (methyl substituents on N) - One ethyl group (main chain) 4. Numbering: The carbon attached to N is position 1 5. Substituents on N: N,N-dimethyl ...

Q4: Describe the reaction of amines with acids. Write the equation for the reaction of aniline with hydrochloric acid.

Reaction of amines with acids: Amines react with acids to form salts (ammonium salts). The nitrogen lone pair acts as a nucleophile and accepts a proton from the acid. General reaction: R3N + HX → R3N-H+ X- For primary amines: R-NH2 + HX → R-NH3+ X- For secondary amines: R2N-H + HX → R2N-H2+ X- Specific example with aniline and HCl: Equation: C6H5NH2 + HCl → C6H5NH3+ Cl- Or written as: C6H5NH2·HCl (aniline hydrochloride) Alternatively: C6H5NH2 + HCl → [C6H5NH3]+Cl- The aniline hydrochlo...

Q5: Explain the Hofmann elimination reaction. Write the equation for the Hofmann elimination of 1-bromopropane.

Hofmann elimination reaction: Elimination reaction of quaternary ammonium salts (produced by exhaustive methylation of primary amines) to form alkenes and a tertiary amine as byproducts. Note: The reaction is actually with 1-bromopropane (primary alkyl halide, not amine). The actual Hofmann reaction requires a quaternary ammonium salt. Let me address the correct interpretation: For a primary amine (to demonstrate Hofmann elimination): Example: CH3CH2CH2NH2 (1-propylamine or propan-1-amine) Ho...

Q6: What happens when aniline is treated with nitrous acid at 0°C? Write the equation and explain the product.

Reaction of aniline with nitrous acid (HNO2) at 0°C: Equation: C6H5NH2 + HNO2 + HCl (at 0°C) → [C6H5N2]+Cl- + 2 H2O Or more clearly: C6H5NH2 + NaNO2 + HCl (0°C) → [C6H5N2]+Cl- (diazonium salt) + NaCl + 2 H2O Product name: Benzenediazonium chloride (or phenyldiazonium chloride) Product structure: C6H5-N≡N+ Cl- Step-by-step mechanism: Step 1: Formation of nitrous acid in situ NaNO2 + HCl → HNO2 + NaCl HNO2 is the active reagent Step 2: Protonation of aniline C6H5NH2 + H+ → C6H5NH3+ Step 3: ...

Showing 6 of 7 questions. Visit the full page for complete solutions.

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