Amines — Class 12 Chemistry NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Amines" — 7 important questions with detailed answers for CBSE board exam preparation.
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TL;DR: Free step-by-step NCERT solutions for Class 12 Chemistry chapter "Amines" — 7 important questions with detailed answers for CBSE board exam preparatio…
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Key Questions Covered:
- Define amines. What is the difference between primary, secondary, and tertiar…
- Explain the basicity of amines. Why are amines basic in character? Compare th…
- Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its structure and classify …
- Describe the reaction of amines with acids. Write the equation for the reacti…
- Explain the Hofmann elimination reaction. Write the equation for the Hofmann …
- What happens when aniline is treated with nitrous acid at 0°C? Write the equa…
- + 1 more questions in the full chapter
Solutions Summary:
| Question | Status |
|---|---|
| Define amines. What is the difference between primary, se… | ✓ Solved |
| Explain the basicity of amines. Why are amines basic in c… | ✓ Solved |
| Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its str… | ✓ Solved |
| Describe the reaction of amines with acids. Write the equ… | ✓ Solved |
| Explain the Hofmann elimination reaction. Write the equat… | ✓ Solved |
| What happens when aniline is treated with nitrous acid at… | ✓ Solved |
Showing 6 of 7 questions
Q1: Define amines. What is the difference between primary, secondary, and tertiary amines? Give one example of each.
Amines: Organic compounds derived from ammonia (NH3) by replacement of one, two, or three hydrogen atoms with alkyl or aryl groups.
General formula: R-NH2, R2N-H, or R3N
Classification:
Primary amines (1° amine):
- One hydrogen of ammonia is replaced by an alkyl or aryl group
- General formula: R-NH2
- Contains one N-H bond and one N-C bond
- Example: CH3CH2NH2 (ethylamine or ethanamine)
- Structure: C-NH2
Secondary amines (2° amine):
- Two hydrogens of ammonia are replaced by alkyl or aryl ...
Q2: Explain the basicity of amines. Why are amines basic in character? Compare the basicity of primary, secondary, and tertiary amines.
Basicity of amines:
Amines are basic because they contain a lone pair of electrons on the nitrogen atom. This lone pair can accept a proton (H+) from an acid.
General reaction:
R-NH2 + HX → R-NH3+ + X- (or R-NH3+X-)
The amine acts as a proton acceptor (Lewis base):
R-NH2 + H+ → R-NH3+
Basic strength comparison:
Primary (RNH2) > Tertiary (R3N) > Secondary (R2NH)
Detailed explanation:
1. Basicity order and reasons:
- Primary amines: Strongest (in aliphatic series)
- Tertiary ami...
Q3: Write the IUPAC name of (CH3)2N-CH2-CH3. Describe its structure and classify this amine.
Structure of (CH3)2N-CH2-CH3:
CH3
|
CH3-N-CH2-CH3
|
CH3
Alternative representation: CH3-N(CH3)-CH2-CH3
IUPAC name: N,N-dimethylethanamine
Naming explanation:
1. Main chain: ethane (2 carbons attached to N in the longest chain)
2. Functional group: amine (-amine suffix)
3. The nitrogen is attached to:
- Two methyl groups (methyl substituents on N)
- One ethyl group (main chain)
4. Numbering: The carbon attached to N is position 1
5. Substituents on N: N,N-dimethyl ...
Q4: Describe the reaction of amines with acids. Write the equation for the reaction of aniline with hydrochloric acid.
Reaction of amines with acids:
Amines react with acids to form salts (ammonium salts). The nitrogen lone pair acts as a nucleophile and accepts a proton from the acid.
General reaction:
R3N + HX → R3N-H+ X-
For primary amines:
R-NH2 + HX → R-NH3+ X-
For secondary amines:
R2N-H + HX → R2N-H2+ X-
Specific example with aniline and HCl:
Equation: C6H5NH2 + HCl → C6H5NH3+ Cl-
Or written as: C6H5NH2·HCl (aniline hydrochloride)
Alternatively: C6H5NH2 + HCl → [C6H5NH3]+Cl-
The aniline hydrochlo...
Q5: Explain the Hofmann elimination reaction. Write the equation for the Hofmann elimination of 1-bromopropane.
Hofmann elimination reaction: Elimination reaction of quaternary ammonium salts (produced by exhaustive methylation of primary amines) to form alkenes and a tertiary amine as byproducts.
Note: The reaction is actually with 1-bromopropane (primary alkyl halide, not amine). The actual Hofmann reaction requires a quaternary ammonium salt. Let me address the correct interpretation:
For a primary amine (to demonstrate Hofmann elimination):
Example: CH3CH2CH2NH2 (1-propylamine or propan-1-amine)
Ho...
Q6: What happens when aniline is treated with nitrous acid at 0°C? Write the equation and explain the product.
Reaction of aniline with nitrous acid (HNO2) at 0°C:
Equation:
C6H5NH2 + HNO2 + HCl (at 0°C) → [C6H5N2]+Cl- + 2 H2O
Or more clearly:
C6H5NH2 + NaNO2 + HCl (0°C) → [C6H5N2]+Cl- (diazonium salt) + NaCl + 2 H2O
Product name: Benzenediazonium chloride (or phenyldiazonium chloride)
Product structure: C6H5-N≡N+ Cl-
Step-by-step mechanism:
Step 1: Formation of nitrous acid in situ
NaNO2 + HCl → HNO2 + NaCl
HNO2 is the active reagent
Step 2: Protonation of aniline
C6H5NH2 + H+ → C6H5NH3+
Step 3: ...
Showing 6 of 7 questions. Visit the full page for complete solutions.
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