Areas — Telangana (SSC) Class 9 Mathematics Solutions (Free)
Free step-by-step Telangana (SSC) Class 9 Mathematics solutions for "Areas" — important questions with detailed answers, download PDF for board exam preparation.
TL;DR: Free step-by-step Telangana (SSC) Class 9 Mathematics solutions for "Areas" — important questions with detailed answers, download PDF for board exam p…
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Q1: Find the area of a triangle with base 12 cm and height 8 cm.
Step 1: Area of triangle = (1/2) × base × height
Step 2: Area = (1/2) × 12 × 8
Step 3: Area = (1/2) × 96 = 48 cm²
Final Answer: Area = 48 cm²
Q2: Find the area of a parallelogram with base 10 cm and height 6 cm.
Step 1: Area of parallelogram = base × height
Step 2: Area = 10 × 6 = 60 cm²
Final Answer: Area = 60 cm²
Q3: Find the area of a trapezoid with parallel sides 8 cm and 12 cm, and height 5 cm.
Step 1: Area of trapezoid = (1/2) × (sum of parallel sides) × height
Step 2: Area = (1/2) × (8 + 12) × 5
Step 3: Area = (1/2) × 20 × 5 = (1/2) × 100 = 50 cm²
Final Answer: Area = 50 cm²
Q4: Find the area of a rhombus with diagonals 16 cm and 12 cm.
Step 1: Area of rhombus = (1/2) × d₁ × d₂ where d₁, d₂ are diagonals
Step 2: Area = (1/2) × 16 × 12
Step 3: Area = (1/2) × 192 = 96 cm²
Final Answer: Area = 96 cm²
Q5: Find the area of a circle with radius 7 cm.
Step 1: Area of circle = πr²
Step 2: Area = π × 7² = 49π cm²
Step 3: Area ≈ 49 × 3.14159 ≈ 153.94 cm²
Final Answer: Area = 49π cm² ≈ 153.94 cm²
Showing 5 of 8 questions — full solutions on the page.