Refraction of Light at Curved Surfaces — Telangana (SSC) Class 10 Science Solutions (Free)
Free step-by-step Telangana (SSC) Class 10 Science solutions for "Refraction of Light at Curved Surfaces" — important questions with detailed answers, download PDF for board exam preparation.
TL;DR: Free step-by-step Telangana (SSC) Class 10 Science solutions for "Refraction of Light at Curved Surfaces" — important questions with detailed answers,…
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Q1: Define refraction of light. State Snell's law.
Refraction: Bending of light when it passes from one medium to another of different optical density.
Snell's Law: n₁ sin θ₁ = n₂ sin θ₂
Where n = refractive index, θ = angle of incidence/refraction
Light bends toward normal when entering denser medium, away from normal when entering rarer medium
Q2: What is a lens? Distinguish between convex and concave lenses.
Lens: A transparent optical device with curved surfaces for refraction of light.
Convex lens (converging): Thicker at center, thinner at edges. Converges parallel rays to focal point. Forms real/virtual images.
Concave lens (diverging): Thinner at center, thicker at edges. Diverges parallel rays. Forms only virtual, erect, diminished images.
Both lenses obey lens formula and follow sign convention
Q3: A convex lens has focal length 20 cm. Find image position and nature when object is at 40 cm.
Step 1: Given f = 20 cm, u = 40 cm (object distance)
Step 2: Use lens formula 1/f = 1/v + 1/u
Step 3: 1/20 = 1/v + 1/40 → 1/v = 1/20 - 1/40 = 1/40
Step 4: v = 40 cm (image distance)
Step 5: Magnification m = v/u = 40/40 = 1
Image is at 40 cm, real, inverted, same size as object (magnification = 1)
Q4: Define focal length and power of a lens.
Focal length (f): Distance between optical center and focal point of a lens.
For convex lens, f is positive; for concave lens, f is negative.
Power (P): Reciprocal of focal length in meters.
P = 1/f (in diopters, D)
Example: f = 20 cm = 0.2 m, P = 1/0.2 = +5 D (convex lens)
Q5: A concave lens has focal length 15 cm. Where will image form if object is at 30 cm?
Step 1: Given f = -15 cm (concave, negative), u = 30 cm
Step 2: Use lens formula 1/f = 1/v + 1/u
Step 3: 1/(-15) = 1/v + 1/30 → 1/v = -1/15 - 1/30 = -3/30 = -1/10
Step 4: v = -10 cm
Image forms at 10 cm on the same side as object, virtual, erect, diminished
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