Reflection of Light at Curved Surfaces — Telangana (SSC) Class 10 Science Solutions (Free)
Free step-by-step Telangana (SSC) Class 10 Science solutions for "Reflection of Light at Curved Surfaces" — important questions with detailed answers, download PDF for board exam preparation.
TL;DR: Free step-by-step Telangana (SSC) Class 10 Science solutions for "Reflection of Light at Curved Surfaces" — important questions with detailed answers,…
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Q1: Define focal length of a spherical mirror.
Focal length (f) is the distance between the pole (P) of the mirror and its focal point (F).
It is half the radius of curvature: f = R/2
Where R is the radius of curvature of the mirror.
Q2: A concave mirror has radius of curvature 20 cm. Find its focal length.
Step 1: Given R = 20 cm
Step 2: Use formula f = R/2
Step 3: f = 20/2 = 10 cm
Focal length = 10 cm
Q3: An object 4 cm tall is placed 30 cm from a concave mirror of focal length 10 cm. Find image distance and magnification.
Step 1: Given h = 4 cm, u = 30 cm, f = 10 cm
Step 2: Use mirror formula 1/f = 1/v + 1/u
Step 3: 1/10 = 1/v + 1/30 → 1/v = 1/10 - 1/30 = 2/30 = 1/15
Step 4: v = 15 cm (real image)
Step 5: Magnification m = -v/u = -15/30 = -0.5
Image distance = 15 cm, magnification = -0.5 (inverted, reduced)
Q4: Why does a concave mirror form a real, inverted, diminished image when object is beyond C?
When object is beyond center of curvature (C):
• Light rays converge after reflection
• Image forms between C and F on the same side
• Image is real (can be projected on screen), inverted, and smaller than object
• This follows from the principle that rays obey mirror formula and geometry
Q5: What is the power of a concave mirror with focal length 25 cm?
Step 1: Given f = 25 cm = 0.25 m
Step 2: Power P = 1/f (in diopters, when f in meters)
Step 3: P = 1/0.25 = +4 diopters
Power = +4 D (positive because it's concave/converging)
Showing 5 of 7 questions — full solutions on the page.