Reflection of Light at Curved Surfaces — Telangana (SSC) Class 10 Science Solutions (Free)

Free step-by-step Telangana (SSC) Class 10 Science solutions for "Reflection of Light at Curved Surfaces" — important questions with detailed answers, download PDF for board exam preparation.

Reflection of Light at Curved Surfaces — Telangana (SSC) Class 10 Science Solutions (Free)

Free step-by-step Telangana (SSC) Class 10 Science solutions for "Reflection of Light at Curved Surfaces" — important questions with detailed answers, download PDF for board exam preparation.

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TL;DR: Free step-by-step Telangana (SSC) Class 10 Science solutions for "Reflection of Light at Curved Surfaces" — important questions with detailed answers,…

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Reflection of Light at Curved Surfaces — Textbook Questions Answered (7)

Q1: Define focal length of a spherical mirror.

Focal length (f) is the distance between the pole (P) of the mirror and its focal point (F). It is half the radius of curvature: f = R/2 Where R is the radius of curvature of the mirror.

Q2: A concave mirror has radius of curvature 20 cm. Find its focal length.

Step 1: Given R = 20 cm Step 2: Use formula f = R/2 Step 3: f = 20/2 = 10 cm Focal length = 10 cm

Q3: An object 4 cm tall is placed 30 cm from a concave mirror of focal length 10 cm. Find image distance and magnification.

Step 1: Given h = 4 cm, u = 30 cm, f = 10 cm Step 2: Use mirror formula 1/f = 1/v + 1/u Step 3: 1/10 = 1/v + 1/30 → 1/v = 1/10 - 1/30 = 2/30 = 1/15 Step 4: v = 15 cm (real image) Step 5: Magnification m = -v/u = -15/30 = -0.5 Image distance = 15 cm, magnification = -0.5 (inverted, reduced)

Q4: Why does a concave mirror form a real, inverted, diminished image when object is beyond C?

When object is beyond center of curvature (C): • Light rays converge after reflection • Image forms between C and F on the same side • Image is real (can be projected on screen), inverted, and smaller than object • This follows from the principle that rays obey mirror formula and geometry

Q5: What is the power of a concave mirror with focal length 25 cm?

Step 1: Given f = 25 cm = 0.25 m Step 2: Power P = 1/f (in diopters, when f in meters) Step 3: P = 1/0.25 = +4 diopters Power = +4 D (positive because it's concave/converging)

Q6: Define magnification and state its sign convention for mirrors.

Magnification (m) = height of image / height of object = -v/u Sign convention: m is positive when image is erect (virtual), negative when inverted (real) For mirrors: Real images have negative m, virtual images have positive m

Q7: A concave mirror is used in a shaving mirror. Why?

A concave mirror forms an erect, magnified virtual image when object is between pole and focus. This magnified virtual image helps in proper shaving and grooming. The concave shape concentrates light and provides clear, enlarged view of the face.

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