Electric Current — Telangana (SSC) Class 10 Science Solutions (Free)

Free step-by-step Telangana (SSC) Class 10 Science solutions for "Electric Current" — important questions with detailed answers, download PDF for board exam preparation.

Electric Current — Telangana (SSC) Class 10 Science Solutions (Free)

Free step-by-step Telangana (SSC) Class 10 Science solutions for "Electric Current" — important questions with detailed answers, download PDF for board exam preparation.

✓ 100% Free ✓ No Login Needed ✓ NCERT / CBSE Aligned ✓ Download as PDF

TL;DR: Free step-by-step Telangana (SSC) Class 10 Science solutions for "Electric Current" — important questions with detailed answers, download PDF for boar…

Written & reviewed by the Syllab.in Academic Team (CBSE/NCERT subject experts) · Updated

🤖 Stuck on any question? Ask Syllab's free AI Tutor for a step-by-step explanation — instant, unlimited, no login.

Electric Current — Textbook Questions Answered (7)

Q1: State Ohm's Law and explain what it means.

Ohm's Law states: V = I × R, where V is potential difference (Volts), I is current (Amperes), and R is resistance (Ohms). Meaning: At constant temperature, the potential difference across a conductor is directly proportional to the current flowing through it. The ratio V/I remains constant for a given conductor and is called its resistance. Mathematically: R = V/I

Q2: A wire has resistance 10 Ω. If a potential difference of 50 V is applied, find the current.

Step 1: Given R = 10 Ω, V = 50 V Step 2: Use Ohm's Law: V = I × R Step 3: Rearrange: I = V/R = 50/10 = 5 A Answer: Current = 5 Amperes

Q3: Define electric resistance and list 3 factors affecting it.

Resistance is the opposition offered by a conductor to the flow of electric current through it. Unit: Ohm (Ω). Three factors affecting resistance: 1. Length of conductor (L): Resistance ∝ L (longer wire = higher resistance) 2. Cross-sectional area (A): Resistance ∝ 1/A (thicker wire = lower resistance) 3. Nature of material (ρ): Different materials have different resistivity values Formula: R = ρL/A

Q4: Calculate the power consumed by a device if current 2 A flows through it at 220 V potential difference.

Step 1: Given V = 220 V, I = 2 A Step 2: Power formula: P = V × I Step 3: P = 220 × 2 = 440 W Answer: Power consumed = 440 Watts Alternative: Using P = I²R or P = V²/R if R is known

Q5: What is the difference between series and parallel circuits?

Series Circuit: • Components connected end-to-end in single path • Same current flows through all components • Total resistance: R_total = R₁ + R₂ + R₃... • If one breaks, entire circuit breaks Parallel Circuit: • Components connected with multiple paths • Same voltage across all components • Total resistance: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃... • If one breaks, others still work

Q6: A bulb rated 60 W, 220 V is used for 5 hours. Calculate electrical energy consumed in kWh.

Step 1: Given Power P = 60 W = 0.06 kW, Time t = 5 hours Step 2: Energy formula: E = P × t Step 3: E = 0.06 × 5 = 0.30 kWh Answer: Energy consumed = 0.30 kWh or 0.3 units Cost = 0.3 × Rate (where rate depends on local electricity charges)

Q7: Explain the working principle of a circuit breaker and its importance.

A circuit breaker is a safety device that automatically cuts off electric supply when current exceeds safe limits. Working: When excessive current flows (due to overload or short circuit), the electromagnetic coil in the breaker generates strong magnetic field → trips the switch → breaks the circuit. Importance: 1. Prevents fire caused by overheating of wires 2. Protects electrical appliances from damage 3. Saves lives from electric shock 4. Can be reset after tripping (unlike fuse which melts permanently)

Related