Laws of Motion — Maharashtra (SSC) Class 9 Science Solutions (Free)
Free step-by-step Maharashtra (SSC) Class 9 Science solutions for "Laws of Motion" — important questions with detailed answers, download PDF for board exam preparation.
TL;DR: Free step-by-step Maharashtra (SSC) Class 9 Science solutions for "Laws of Motion" — important questions with detailed answers, download PDF for board…
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Q1: State Newton's first law of motion with an example.
Newton's 1st law: A body at rest remains at rest, and a body in motion remains in uniform motion unless an external force acts on it. Example: A passenger in a moving bus leans backward when the bus suddenly stops because their body tends to continue moving forward due to inertia.
Q2: A force of 10 N is applied to a 2 kg mass. Calculate the acceleration produced.
Using Newton's 2nd law: F = ma
Step 1: Given F = 10 N, m = 2 kg
Step 2: a = F/m = 10/2 = 5 m/s²
Acceleration = 5 m/s²
Q3: Define momentum and state the law of conservation of momentum.
Momentum (p) = mass × velocity = mv (unit: kg·m/s). Law of conservation: Total momentum of a system remains constant if no external force acts on it. Example: In a collision between two balls, momentum before = momentum after if no friction/external forces.
Q4: Two balls of mass 3 kg and 2 kg move at 4 m/s and 6 m/s respectively in opposite directions. Calculate total momentum.
Step 1: Take one direction as positive. m₁ = 3 kg, v₁ = 4 m/s; m₂ = 2 kg, v₂ = -6 m/s
Step 2: p₁ = 3 × 4 = 12 kg·m/s; p₂ = 2 × (-6) = -12 kg·m/s
Step 3: Total momentum = 12 + (-12) = 0 kg·m/s
Q5: State Newton's third law and explain action-reaction pairs.
Newton's 3rd law: For every action, there is an equal and opposite reaction. Example: When you push a wall, the wall pushes you back with equal force. Both forces act on different bodies, are equal in magnitude, opposite in direction, and occur simultaneously.
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