Effects of Electric Current — Maharashtra (SSC) Class 10 Science Solutions (Free)

Free step-by-step Maharashtra (SSC) Class 10 Science solutions for "Effects of Electric Current" — important questions with detailed answers, download PDF for board exam preparation.

Effects of Electric Current — Maharashtra (SSC) Class 10 Science Solutions (Free)

Free step-by-step Maharashtra (SSC) Class 10 Science solutions for "Effects of Electric Current" — important questions with detailed answers, download PDF for board exam preparation.

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Effects of Electric Current — Textbook Questions Answered (7)

Q1: Define electric current and state Ohm's law. What are its limitations?

Electric current is the flow of electric charge per unit time. Unit: Ampere (A). Current = charge/time = Q/t. Ohm's law: V = IR, where V is potential difference, I is current, R is resistance. At constant temperature, current through conductor is directly proportional to applied potential difference. Limitations: Does not apply to non-ohmic conductors (semiconductors, gases at low pressure), at very high temperatures, or to some nonlinear devices like diodes and transistors.

Q2: A wire has resistance 10 ohm. If 2 A current flows through it, find potential difference.

Step 1: Given R = 10 ohm, I = 2 A Step 2: Use Ohm's law: V = IR Step 3: V = 2 x 10 = 20 V Answer: Potential difference is 20 V. This means 20 joules of energy is given to each coulomb of charge passing through the wire.

Q3: Describe the heating effect of electric current. On what factors does it depend?

Heating effect: When current flows through a conductor, it generates heat due to friction between moving electrons and atoms. Formula: Heat = I2Rt (Joule's law of heating). Factors: (1) Current (I): Heat is proportional to square of current, (2) Resistance (R): Heat is directly proportional to resistance, (3) Time (t): Heat is proportional to time of flow. Higher current, higher resistance, or longer duration produces more heat. Used in heaters, bulbs, electric stoves.

Q4: Calculate heat produced when 5 A current flows through 20 ohm resistor for 10 seconds.

Step 1: Given I = 5 A, R = 20 ohm, t = 10 s Step 2: Use Joule's law: H = I2Rt Step 3: H = (5)2 x 20 x 10 Step 4: H = 25 x 20 x 10 = 5000 J Answer: Heat produced is 5000 joules or 5 kJ. This heat warms the conductor and surroundings.

Q5: What is the magnetic effect of electric current? How is it used in electromagnetic devices?

Magnetic effect: When current flows through a conductor, a magnetic field is produced around it. Direction: Given by right-hand rule (thumb in current direction, fingers curl in field direction). Strength increases with current. Uses: (1) Electromagnets in electric bells, door locks, relays, (2) Magnetic field in electric motors, (3) Solenoids in switches. Current-carrying coil acts like a magnet. Strength can be controlled by changing current.

Q6: Define power and energy in electrical circuit. Calculate power for 10 V, 5 A.

Power: Rate of energy consumption or transfer. Formula: P = VI = I2R = V2/R. Unit: Watt (W). Energy: Work done by electric current. Formula: E = Pt = VIt. Unit: Joule (J) or kWh. Calculation: P = VI = 10 x 5 = 50 W. This means 50 joules of energy is dissipated per second. In 1 hour, energy = 50 x 3600 = 180000 J = 0.05 kWh.

Q7: Name three appliances that use heating effect and three that use magnetic effect of current.

Heating effect: (1) Electric heater/geyser, (2) Incandescent bulb (filament glows), (3) Electric stove/cooker, (4) Toaster. Magnetic effect: (1) Electric bell (electromagnet attracts armature), (2) Electric motor (coil rotates in magnetic field), (3) Relay (electromagnet controls switch), (4) Solenoid (creates magnetic field). Some devices use both effects, like microwave (magnetic field generation plus heating).

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