Chemical Reactions and Equations — Maharashtra (SSC) Class 10 Science Solutions (Free)
Free step-by-step Maharashtra (SSC) Class 10 Science solutions for "Chemical Reactions and Equations" — important questions with detailed answers, download PDF for board exam preparation.
TL;DR: Free step-by-step Maharashtra (SSC) Class 10 Science solutions for "Chemical Reactions and Equations" — important questions with detailed answers, dow…
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Q1: Define chemical reaction and chemical equation. What is meant by balancing?
Chemical reaction: A process in which reactants are transformed into products with breaking and formation of chemical bonds. Chemical equation: A symbolic representation of a chemical reaction using chemical formulas and coefficients. Balancing: Adjusting coefficients so that number of atoms of each element is equal on both sides. Balanced equation shows the correct molar ratios of reactants and products.
Q2: Balance the equation: Fe + O2 -> Fe2O3
Step 1: Count atoms on both sides: Fe: 1 left, 2 right; O: 2 left, 3 right
Step 2: Balance Fe: Multiply Fe by 4 and Fe2O3 by 2 -> 4Fe + O2 -> 2Fe2O3
Step 3: Count O: Left has 2, right has 6 (2 x 3). Multiply O2 by 3
Step 4: 4Fe + 3O2 -> 2Fe2O3
Step 5: Verify: Fe = 4 on both sides, O = 6 on both sides. Balanced.
Q3: Classify the following reactions: (1) CaCO3 -> CaO + CO2 (2) H2 + Cl2 -> 2HCl (3) AgNO3 + NaCl -> AgCl + NaNO3
(1) Decomposition reaction: Single reactant breaks into multiple products due to heat. (2) Combination or synthesis reaction: Two reactants combine to form one product. (3) Displacement or double displacement reaction: Ions exchange partners. Ag+ exchanges with Na+, Cl- exchanges with NO3-. AgCl is precipitate (insoluble). All are irreversible reactions in forward direction.
Q4: Define redox reaction. What are oxidation and reduction?
Redox reaction: A reaction in which oxidation and reduction occur simultaneously. Oxidation: Loss of electrons (or gain of oxygen or loss of hydrogen). Reduction: Gain of electrons (or loss of oxygen or gain of hydrogen). Example: 2Cu + O2 -> 2CuO. Here, Cu loses electrons (oxidized), O2 gains electrons (reduced). Oxidizing agent: Substance that causes oxidation (O2). Reducing agent: Substance that causes reduction (Cu).
Q5: Identify oxidation and reduction in: Zn + CuSO4 -> ZnSO4 + Cu
Step 1: Determine oxidation states. Zn: 0 -> +2 (loses 2 electrons, oxidized). Cu: +2 -> 0 (gains 2 electrons, reduced).
Step 2: Oxidation occurs at Zn atom (reducing agent). Reduction occurs at Cu atom (oxidizing agent).
Step 3: Electrons lost by Zn = electrons gained by Cu = 2 electrons.
This is a displacement reaction where more reactive Zn displaces Cu from its compound.
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