Lines and Angles — Karnataka (SSLC) Class 9 Mathematics Solutions (Free)

Free step-by-step Karnataka (SSLC) Class 9 Mathematics solutions for "Lines and Angles" — important questions with detailed answers, download PDF for board exam preparation.

Lines and Angles — Karnataka (SSLC) Class 9 Mathematics Solutions (Free)

Free step-by-step Karnataka (SSLC) Class 9 Mathematics solutions for "Lines and Angles" — important questions with detailed answers, download PDF for board exam preparation.

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Lines and Angles — Textbook Questions Answered (8)

Q1: A transversal intersects two lines, making angles of 80° and 100° on the same side of the transversal. Are the two lines parallel?

Two lines cut by a transversal are parallel if the co-interior (same-side interior) angles are supplementary, adding up to 180°. 80° + 100° = 180° Since the sum is exactly 180°, the lines ARE parallel.

Q2: Two straight lines intersect, and one of the four angles formed is 62°. Find the other three angles.

When two lines intersect, vertically opposite angles are equal, and each pair of adjacent angles forms a linear pair summing to 180°. Given angle: 62°. Its vertically opposite angle is also 62°. Each adjacent angle: 180° − 62° = 118°. The four angles, going around the point of intersection, are: 62°, 118°, 62°, 118°.

Q3: In triangle ABC, ∠A = 55° and ∠B = 75°. Find ∠C and verify the angle sum property.

Angle sum property: ∠A + ∠B + ∠C = 180°. 55° + 75° + ∠C = 180° ∠C = 180° − 130° ∠C = 50° Verification: 55° + 75° + 50° = 180° ✓

Q4: An exterior angle of a triangle is 130°, and one non-adjacent interior angle is 70°. Find the other non-adjacent interior angle.

By the Exterior Angle Theorem, an exterior angle equals the sum of the two non-adjacent interior angles. 130° = 70° + x x = 130° − 70° x = 60° The other non-adjacent interior angle is 60°.

Q5: A line makes an angle of 145° with the positive x-axis. What angle does it make with the negative x-axis?

The positive and negative x-axis together form a straight line, so the two angles the line makes with them are supplementary. Angle with negative x-axis = 180° − 145° = 35°.

Q6: Two parallel lines are cut by a transversal. One alternate interior angle is (5x − 10)° and the other is (4x + 15)°. Find x and both angles.

Alternate interior angles formed by a transversal cutting two parallel lines are equal. 5x − 10 = 4x + 15 5x − 4x = 15 + 10 x = 25 Substitute back: First angle = 5(25) − 10 = 125 − 10 = 115° Second angle = 4(25) + 15 = 100 + 15 = 115° Both angles equal 115°, confirming x = 25.

Q7: Three angles (x + 5)°, (2x + 10)°, and (3x − 15)° lie along a straight line. Find all three angles.

Angles forming a straight line add up to 180°. (x + 5) + (2x + 10) + (3x − 15) = 180 6x = 180 x = 30 Substituting back: First angle = 30 + 5 = 35° Second angle = 2(30) + 10 = 70° Third angle = 3(30) − 15 = 75° Verification: 35° + 70° + 75° = 180° ✓

Q8: Prove that the sum of the interior angles of a quadrilateral is 360°.

Given: A quadrilateral PQRS. To prove: ∠P + ∠Q + ∠R + ∠S = 360° Proof: Step 1: Draw diagonal PR, splitting the quadrilateral into two triangles: △PQR and △PRS. Step 2: In △PQR, the angles sum to 180°: ∠QPR + ∠Q + ∠QRP = 180°. Step 3: In △PRS, the angles sum to 180°: ∠SPR + ∠S + ∠SRP = 180°. Step 4: Adding these: (∠QPR + ∠SPR) + ∠Q + (∠QRP + ∠SRP) + ∠S = 360°. Step 5: Since ∠QPR + ∠SPR = ∠P (the full angle at P) and ∠QRP + ∠SRP = ∠R (the full angle at R): ∠P + ∠Q + ∠R + ∠S = 360° Hence proved.

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