Surface Areas and Volumes — Andhra Pradesh (SSC) Class 9 Mathematics Solutions (Free)
Free step-by-step Andhra Pradesh (SSC) Class 9 Mathematics solutions for "Surface Areas and Volumes" — important questions with detailed answers, download PDF for board exam preparation.
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Surface Areas and Volumes — Textbook Questions Answered (8)
Q1: Find the total surface area and volume of a cuboid (rectangular prism) with length 12 cm, breadth 8 cm, and height 6 cm.
Step 1: Cuboid dimensions:
Length (l) = 12 cm
Breadth (b) = 8 cm
Height (h) = 6 cm
Step 2: Total Surface Area of Cuboid:
Formula: Total Surface Area = 2(lb + bh + hl)
Step 3: Calculate each product:
lb = 12 × 8 = 96 cm²
bh = 8 × 6 = 48 cm²
hl = 6 × 12 = 72 cm²
Step 4: Sum of products:
lb + bh + hl = 96 + 48 + 72 = 216 cm²
Step 5: Calculate surface area:
Total Surface Area = 2 × 216 = 432 cm²
Step 6: Volume of Cuboid:
Formula: Volume = l × b × h
Volume = 12 × 8 × 6
Volume = 96 × 6
Volume = 576 cm³
Step 7: Verification:
The cuboid has:
- 2 rectangular faces of dimensions 12 × 8 cm
- 2 rectangular faces of dimensions 8 × 6 cm
- 2 rectangular faces of dimensions 6 × 12 cm
Total surface area = 2(96) + 2(48) + 2(72) = 192 + 96 + 144 = 432 cm² ✓
Answer: Total Surface Area = 432 cm²; Volume = 576 cm³.
Q2: A cylinder has radius 7 cm and height 10 cm. Find its curved surface area, total surface area, and volume.
Step 1: Cylinder dimensions:
Radius (r) = 7 cm
Height (h) = 10 cm
Step 2: Curved Surface Area (Lateral Surface Area):
Formula: Curved Surface Area = 2πrh
Curved Surface Area = 2 × π × 7 × 10
Curved Surface Area = 140π cm²
Curved Surface Area ≈ 140 × 3.14159 ≈ 439.82 cm²
Step 3: Area of Two Circular Bases:
Area of one circle = πr²
Area of one circle = π × 7²
Area of one circle = 49π cm²
Area of two circles = 2 × 49π = 98π cm²
Area of two circles ≈ 98 × 3.14159 ≈ 307.88 cm²
Step 4: Total Surface Area:
Total Surface Area = Curved Surface Area + Area of two bases
Total Surface Area = 140π + 98π
Total Surface Area = 238π cm²
Total Surface Area ≈ 238 × 3.14159 ≈ 747.70 cm²
Step 5: Volume of Cylinder:
Formula: Volume = πr²h
Volume = π × 7² × 10
Volume = π × 49 × 10
Volume = 490π cm³
Volume ≈ 490 × 3.14159 ≈ 1539.38 cm³
Answer: Curved Surface Area = 140π cm² ≈ 439.82 cm²; Total Surface Area = 238π cm² ≈ 747.70 cm²; Volume = 490π cm³ ≈ 1539.38 cm³.
Q3: A cone has base radius 5 cm, height 12 cm. Find the slant height, curved surface area, total surface area, and volume.
Step 1: Cone dimensions:
Base radius (r) = 5 cm
Height (h) = 12 cm
Slant height (l) = ?
Step 2: Find slant height using Pythagoras theorem:
The slant height, radius, and height form a right triangle.
l² = r² + h²
l² = 5² + 12²
l² = 25 + 144
l² = 169
l = 13 cm
Step 3: Curved Surface Area (Lateral Surface Area):
Formula: Curved Surface Area = πrl
Curved Surface Area = π × 5 × 13
Curved Surface Area = 65π cm²
Curved Surface Area ≈ 65 × 3.14159 ≈ 204.20 cm²
Step 4: Area of Circular Base:
Area of base = πr²
Area of base = π × 5²
Area of base = 25π cm²
Area of base ≈ 25 × 3.14159 ≈ 78.54 cm²
Step 5: Total Surface Area:
Total Surface Area = Curved Surface Area + Base Area
Total Surface Area = 65π + 25π
Total Surface Area = 90π cm²
Total Surface Area ≈ 90 × 3.14159 ≈ 282.74 cm²
Step 6: Volume of Cone:
Formula: Volume = (1/3)πr²h
Volume = (1/3) × π × 5² × 12
Volume = (1/3) × π × 25 × 12
Volume = (1/3) × 300π
Volume = 100π cm³
Volume ≈ 100 × 3.14159 ≈ 314.16 cm³
Answer: Slant height = 13 cm; Curved Surface Area = 65π cm² ≈ 204.20 cm²; Total Surface Area = 90π cm² ≈ 282.74 cm²; Volume = 100π cm³ ≈ 314.16 cm³.
Q4: A sphere has radius 6 cm. Find its surface area and volume.
Step 1: Sphere radius:
r = 6 cm
Step 2: Surface Area of Sphere:
Formula: Surface Area = 4πr²
Surface Area = 4 × π × 6²
Surface Area = 4 × π × 36
Surface Area = 144π cm²
Surface Area ≈ 144 × 3.14159 ≈ 452.39 cm²
Step 3: Volume of Sphere:
Formula: Volume = (4/3)πr³
Volume = (4/3) × π × 6³
Volume = (4/3) × π × 216
Volume = (4/3 × 216) × π
Volume = (864/3) × π
Volume = 288π cm³
Volume ≈ 288 × 3.14159 ≈ 904.78 cm³
Step 4: Verification:
For r = 6:
4πr² = 4π(6)² = 144π ✓
(4/3)πr³ = (4/3)π(6)³ = (4/3)π(216) = 288π ✓
Answer: Surface Area = 144π cm² ≈ 452.39 cm²; Volume = 288π cm³ ≈ 904.78 cm³.
Q5: A hemisphere has radius 8 cm. Find its curved surface area, total surface area (curved + base), and volume.
Step 1: Hemisphere radius:
r = 8 cm
Step 2: Curved Surface Area (curved part only):
Formula: Curved Surface Area = 2πr²
Curved Surface Area = 2 × π × 8²
Curved Surface Area = 2 × π × 64
Curved Surface Area = 128π cm²
Curved Surface Area ≈ 128 × 3.14159 ≈ 402.12 cm²
Step 3: Area of Circular Base:
Area of base = πr²
Area of base = π × 8²
Area of base = 64π cm²
Area of base ≈ 64 × 3.14159 ≈ 201.06 cm²
Step 4: Total Surface Area:
Total Surface Area = Curved Surface Area + Base Area
Total Surface Area = 128π + 64π
Total Surface Area = 192π cm²
Total Surface Area ≈ 192 × 3.14159 ≈ 603.19 cm²
Step 5: Volume of Hemisphere:
Formula: Volume = (2/3)πr³
Volume = (2/3) × π × 8³
Volume = (2/3) × π × 512
Volume = (2/3 × 512) × π
Volume = (1024/3) × π
Volume ≈ 341.33π cm³
Volume ≈ 341.33 × 3.14159 ≈ 1072.33 cm³
Step 6: Relationship check:
A full sphere with radius 8 has volume (4/3)π(8)³ = (4/3)π(512) = (2048/3)π cm³
A hemisphere is half: (1/3) × (2048/3)π = (1024/3)π cm³ ✓
Answer: Curved Surface Area = 128π cm² ≈ 402.12 cm²; Total Surface Area = 192π cm² ≈ 603.19 cm²; Volume = (1024/3)π cm³ ≈ 1072.33 cm³.
Q6: A cube has side length 5 cm. Find its total surface area, lateral surface area, and volume.
Step 1: Cube side length:
a = 5 cm
Step 2: Total Surface Area of Cube:
A cube has 6 equal square faces.
Formula: Total Surface Area = 6a²
Total Surface Area = 6 × 5²
Total Surface Area = 6 × 25
Total Surface Area = 150 cm²
Step 3: Lateral Surface Area (area of 4 vertical faces):
Formula: Lateral Surface Area = 4a²
Lateral Surface Area = 4 × 5²
Lateral Surface Area = 4 × 25
Lateral Surface Area = 100 cm²
Step 4: Verification:
Total Surface Area = Lateral Surface Area + 2 × (Base Area)
150 = 100 + 2 × 25
150 = 100 + 50
150 = 150 ✓
Step 5: Volume of Cube:
Formula: Volume = a³
Volume = 5³
Volume = 125 cm³
Step 6: Diagonal of the cube:
Body diagonal = a√3 = 5√3 cm ≈ 8.66 cm
(This is the distance from one corner to the opposite corner through the interior.)
Answer: Total Surface Area = 150 cm²; Lateral Surface Area = 100 cm²; Volume = 125 cm³.
Q7: Compare the volumes of a cylinder and a cone with the same base radius 4 cm and height 9 cm. Show the relationship between them.
Step 1: Cylinder with radius 4 cm and height 9 cm:
Volume of cylinder = πr²h
Volume of cylinder = π × 4² × 9
Volume of cylinder = π × 16 × 9
Volume of cylinder = 144π cm³
Step 2: Cone with radius 4 cm and height 9 cm:
Volume of cone = (1/3)πr²h
Volume of cone = (1/3) × π × 4² × 9
Volume of cone = (1/3) × π × 16 × 9
Volume of cone = (1/3) × 144π
Volume of cone = 48π cm³
Step 3: Compare the volumes:
Ratio = Volume of cylinder / Volume of cone
Ratio = 144π / 48π
Ratio = 144 / 48
Ratio = 3
Step 4: Relationship:
Volume of cylinder = 3 × Volume of cone
Or: Volume of cone = (1/3) × Volume of cylinder
Step 5: Physical interpretation:
If you fill a cone with water and pour it into a cylinder with the same base radius and height, it takes exactly 3 cones to fill the cylinder.
Step 6: Numerical values:
Volume of cylinder ≈ 144 × 3.14159 ≈ 452.39 cm³
Volume of cone ≈ 48 × 3.14159 ≈ 150.80 cm³
Ratio ≈ 452.39 / 150.80 ≈ 3 ✓
Answer: Volume of cylinder = 144π cm³ ≈ 452.39 cm³; Volume of cone = 48π cm³ ≈ 150.80 cm³. The cylinder's volume is exactly 3 times the cone's volume.
Q8: A rectangular tank has dimensions 2 m × 1.5 m × 1 m. Find how many liters of water it can hold. (1 m³ = 1000 liters)
Step 1: Tank dimensions (cuboid):
Length (l) = 2 m
Breadth (b) = 1.5 m
Height (h) = 1 m
Step 2: Volume of the tank:
Volume = l × b × h
Volume = 2 × 1.5 × 1
Volume = 3 m³
Step 3: Convert to liters:
Given: 1 m³ = 1000 liters
Capacity of tank = 3 × 1000 = 3000 liters
Step 4: Additional calculations:
Surface area of tank (if we need to know surface area of material used):
Total Surface Area = 2(lb + bh + lh)
Total Surface Area = 2(2×1.5 + 1.5×1 + 1×2)
Total Surface Area = 2(3 + 1.5 + 2)
Total Surface Area = 2(6.5)
Total Surface Area = 13 m²
Step 5: If the tank is filled to 3/4 of its capacity:
Water volume = (3/4) × 3 = 2.25 m³ = 2250 liters
Answer: The tank can hold 3000 liters of water.
Related
- NCERT Solutions: Surface Areas and Volumes — the CBSE version of this same topic.
- Number System — more Andhra Pradesh (SSC) Class 9 Mathematics.
- Polynomials — more Andhra Pradesh (SSC) Class 9 Mathematics.
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