Sequences and Series Solved Examples (Class 11 Mathematics)

Sequences are ordered lists of numbers; series are sums of sequence terms. These examples cover arithmetic and geometric sequences, their sums, and applica

Sequences and Series Solved Examples (Class 11 Mathematics)

Sequences are ordered lists of numbers; series are sums of sequence terms. These examples cover arithmetic and geometric sequences, their sums, and applica

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TL;DR: Sequences are ordered lists of numbers; series are sums of sequence terms. These examples cover arithmetic and geometric sequences, their sums, and ap…

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Sequences are ordered lists of numbers; series are sums of sequence terms. These examples cover arithmetic and geometric sequences, their sums, and applica

Sequences and Series — Solved Numerical Examples (Step by Step)

Example 1: Find the 10th term of the arithmetic sequence 5, 9, 13, 17, ...

Solution: For arithmetic sequence with first term a and common difference d:
a_n = a + (n-1)d

Given: a = 5, d = 9 - 5 = 4, n = 10

a_10 = 5 + (10-1) × 4
a_10 = 5 + 9 × 4
a_10 = 5 + 36 = 41

Example 2: Find the sum of first 20 terms of the arithmetic sequence 2, 5, 8, 11, ...

Solution: For arithmetic sequence:
S_n = n/2 × (2a + (n-1)d) = n/2 × (a + l)
Where l is the last term

Given: a = 2, d = 3, n = 20

Method 1: S_20 = 20/2 × (2(2) + (20-1) × 3)
S_20 = 10 × (4 + 57)
S_20 = 10 × 61 = 610

Method 2: First find 20th term:
a_20 = 2 + 19(3) = 2 + 57 = 59
S_20 = 20/2 × (2 + 59) = 10 × 61 = 610

Example 3: Find the 5th term of the geometric sequence 2, 6, 18, 54, ...

Solution: For geometric sequence:
a_n = a × r^(n-1)
Where r is common ratio

Given: a = 2, r = 6/2 = 3, n = 5

a_5 = 2 × 3^(5-1)
a_5 = 2 × 3^4
a_5 = 2 × 81 = 162

Example 4: Find the sum of first 8 terms of the geometric sequence 1, 2, 4, 8, ...

Solution: For geometric sequence:
S_n = a(r^n - 1) / (r - 1) when r ≠ 1

Given: a = 1, r = 2, n = 8

S_8 = 1 × (2^8 - 1) / (2 - 1)
S_8 = (256 - 1) / 1
S_8 = 255

Example 5: Find the sum of the infinite geometric series 1 + 1/2 + 1/4 + 1/8 + ...

Solution: For infinite geometric series with |r| < 1:
S_∞ = a / (1 - r)

Given: a = 1, r = 1/2
Since |r| = 1/2 < 1, series converges.

S_∞ = 1 / (1 - 1/2)
S_∞ = 1 / (1/2) = 2

Example 6: How many terms of the arithmetic sequence 5, 8, 11, ... sum to 185?

Solution: Given: a = 5, d = 3, S_n = 185
Find: n

Using S_n = n/2 × (2a + (n-1)d)
185 = n/2 × (2(5) + (n-1) × 3)
185 = n/2 × (10 + 3n - 3)
185 = n/2 × (7 + 3n)
370 = n(7 + 3n)
370 = 7n + 3n²
3n² + 7n - 370 = 0

Using quadratic formula:
n = (-7 ± √(49 + 4440)) / 6 = (-7 ± √4489) / 6
n = (-7 ± 67) / 6
n = 60/6 = 10 or n = -74/6 (rejected, negative)

n = 10

Example 7: Find the sum of 1² + 2² + 3² + ... + 10².

Solution: Use formula for sum of squares:
Σ(k²) from k=1 to n = n(n+1)(2n+1) / 6

For n = 10:
Σ(k²) = 10 × 11 × 21 / 6
Σ(k²) = 2310 / 6
Σ(k²) = 385

Tips

  • Arithmetic sequence: constant difference d between consecutive terms; a_n = a + (n-1)d.
  • Geometric sequence: constant ratio r between consecutive terms; a_n = a × r^(n-1).
  • Sum formulas: S_n = n/2(first + last) for AP; S_n = a(r^n - 1)/(r - 1) for GP.
  • Infinite geometric series converges only when |r| < 1; sum = a/(1-r).

Frequently Asked Questions

When does an infinite geometric series converge?

An infinite geometric series converges only when the absolute value of the common ratio is less than 1 (|r| < 1). If |r| >= 1, the series diverges (sum is infinite or undefined).

What is the difference between a sequence and a series?

A sequence is a list of numbers in a specific order. A series is the sum of the terms of a sequence. For example, 2, 4, 6, 8 is a sequence; 2 + 4 + 6 + 8 = 20 is a series.

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