Electricity Exemplar — Class 10 Science NCERT Solutions (Free)
Free step-by-step NCERT solutions for Class 10 Science chapter "Electricity Exemplar" — 5 important questions with detailed answers for CBSE board exam preparation.
TL;DR: Free step-by-step NCERT solutions for Class 10 Science chapter "Electricity Exemplar" — 5 important questions with detailed answers for CBSE board exa…
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Key Questions Covered:
- Calculate current when 100 C of charge flows in 4 seconds.
- A bulb rated 60 W, 230 V is operated at rated voltage. Calculate resistance a…
- Three resistors 2 Ω, 3 Ω, 6 Ω are connected in parallel. Find equivalent resi…
- A wire has resistance 10 Ω at 0°C. If temperature coefficient α = 0.005 /°C, …
- Two cells of EMF 1.5 V each are connected in series. Find total EMF and total…
Solutions Summary:
| Question | Status |
|---|---|
| Calculate current when 100 C of charge flows in 4 seconds. | ✓ Solved |
| A bulb rated 60 W, 230 V is operated at rated voltage. Ca… | ✓ Solved |
| Three resistors 2 Ω, 3 Ω, 6 Ω are connected in parallel. … | ✓ Solved |
| A wire has resistance 10 Ω at 0°C. If temperature coeffic… | ✓ Solved |
| Two cells of EMF 1.5 V each are connected in series. Find… | ✓ Solved |
Showing 5 of 5 questions
Q1: Calculate current when 100 C of charge flows in 4 seconds.
Current I = Q/t = 100/4 = 25 A.
Q2: A bulb rated 60 W, 230 V is operated at rated voltage. Calculate resistance and current.
Resistance R = V^2/P = (230)^2/60 = 52900/60 ≈ 882 Ω. Current I = P/V = 60/230 ≈ 0.26 A.
Q3: Three resistors 2 Ω, 3 Ω, 6 Ω are connected in parallel. Find equivalent resistance.
1/Rp = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1. So Rp = 1 Ω.
Q4: A wire has resistance 10 Ω at 0°C. If temperature coefficient α = 0.005 /°C, find resistance at 50°C.
R = R0[1 + α(T - T0)]. R = 10[1 + 0.005(50 - 0)] = 10[1 + 0.25] = 10(1.25) = 12.5 Ω.
Q5: Two cells of EMF 1.5 V each are connected in series. Find total EMF and total internal resistance if each has internal resistance 0.5 Ω.
Total EMF = 1.5 + 1.5 = 3 V. Total internal resistance = 0.5 + 0.5 = 1 Ω.
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