Statistics — Class 10 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 10 Mathematics chapter "Statistics" — 9 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 10 Mathematics chapter "Statistics" — 9 important questions with detailed answers for CBSE board exam prep…

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Key Questions Covered:

  1. Find the mean of the following grouped data using the assumed mean method: Cl…
  2. Find the median of the following grouped data: Class Interval: 0-5, 5-10, 10-…
  3. Find the mode of the following grouped data: Class Interval: 10-20, 20-30, 30…
  4. + 6 more questions in the full chapter

Solutions Summary:

Question Status
Find the mean of the following grouped data using the ass… ✓ Solved
Find the median of the following grouped data: Class Inte… ✓ Solved
Find the mode of the following grouped data: Class Interv… ✓ Solved

Showing 3 of 9 questions

Q1: Find the mean of the following grouped data using the assumed mean method: Class Interval: 0-10, 10-20, 20-30, 30-40, 40-50 Frequency: 5, 15, 20, 8, 2

Step 1: Construct the table with class midpoints (x) and deviations (d) from assumed mean 25 Step 2: Assumed mean A = 25 (midpoint of 20-30) Step 3: Class Intervals and calculations: 0-10: midpoint = 5, d = 5-25 = -20, f = 5, fd = -100 10-20: midpoint = 15, d = 15-25 = -10, f = 15, fd = -1...

Q2: Find the median of the following grouped data: Class Interval: 0-5, 5-10, 10-15, 15-20, 20-25 Frequency: 4, 6, 12, 8, 5

Step 1: Find cumulative frequencies 0-5: f = 4, cf = 4 5-10: f = 6, cf = 10 10-15: f = 12, cf = 22 15-20: f = 8, cf = 30 20-25: f = 5, cf = 35 Step 2: Total frequency N = 35 Step 3: N/2 = 35/2 = 17.5 Step 4: Median class is 10-15 (since cf = 22 is just greater than 17.5) Ste...

Q3: Find the mode of the following grouped data: Class Interval: 10-20, 20-30, 30-40, 40-50, 50-60 Frequency: 3, 7, 12, 8, 5

Step 1: The modal class is the class with the highest frequency Step 2: Frequencies: 3, 7, 12, 8, 5 Step 3: Modal class is 30-40 (frequency = 12) Step 4: Mode = L + [(f1 - f0)/(2f1 - f0 - f2)] × h Step 5: Here, L = 30 (lower limit of modal class) Step 6: f1 = 12 (frequency of modal class) Step 7: f0...

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