Coordinate Geometry Exemplar — Class 10 Mathematics NCERT Solutions (Free)

Free step-by-step NCERT solutions for Class 10 Mathematics chapter "Coordinate Geometry Exemplar" — 5 important questions with detailed answers for CBSE board exam preparation.

TL;DR: Free step-by-step NCERT solutions for Class 10 Mathematics chapter "Coordinate Geometry Exemplar" — 5 important questions with detailed answers for CB…

By Syllab.in · Updated Jun 17, 2026

Key Questions Covered:

Find distance between points (3, 4) and (-1, 2).
Find the midpoint of line segment joining (5, -3) and (3, 7).
Find slope of line joining (2, 5) and (4, 9).
Find equation of line with slope 3 passing through (1, 2).
If vertices of triangle are (0, 0), (4, 0), (0, 3), find area.

Solutions Summary:

Question	Status
Find distance between points (3, 4) and (-1, 2).	✓ Solved
Find the midpoint of line segment joining (5, -3) and (3,…	✓ Solved
Find slope of line joining (2, 5) and (4, 9).	✓ Solved
Find equation of line with slope 3 passing through (1, 2).	✓ Solved
If vertices of triangle are (0, 0), (4, 0), (0, 3), find …	✓ Solved

Showing 5 of 5 questions

Q1: Find distance between points (3, 4) and (-1, 2).

Distance = √[(3 - (-1))^2 + (4 - 2)^2] = √[16 + 4] = √20 = 2√5.

Q2: Find the midpoint of line segment joining (5, -3) and (3, 7).

Midpoint = [(5 + 3)/2, (-3 + 7)/2] = (4, 2).

Q3: Find slope of line joining (2, 5) and (4, 9).

Slope m = (9 - 5)/(4 - 2) = 4/2 = 2.

Q4: Find equation of line with slope 3 passing through (1, 2).

Using point-slope form: y - y1 = m(x - x1). So y - 2 = 3(x - 1). Simplifying: y = 3x - 1.

Q5: If vertices of triangle are (0, 0), (4, 0), (0, 3), find area.

Using formula: Area = (1/2)|x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)| = (1/2)|0(0 - 3) + 4(3 - 0) + 0(0 - 0)| = (1/2)|12| = 6 sq units.

Showing 5 of 5 questions. Visit the full page for complete solutions.