Trigonometry (Class 10 Mathematics)
Trigonometry relates the sides and angles of right triangles. The ratios sine, cosine, and tangent are fundamental to solving problems in geometry, physics
TL;DR: Trigonometry relates the sides and angles of right triangles. The ratios sine, cosine, and tangent are fundamental to solving problems in geometry, ph…
Written & reviewed by the Syllab.in Academic Team (CBSE/NCERT subject experts) · Updated
Trigonometry relates the sides and angles of right triangles. The ratios sine, cosine, and tangent are fundamental to solving problems in geometry, physics
Trigonometry MCQs with Answers & Explanations
Q1. In a right triangle, sin(θ) is defined as:
- Opposite/Adjacent
- Hypotenuse/Opposite
- Opposite/Hypotenuse ✓ (correct)
- Adjacent/Hypotenuse
Explanation: sin(θ) = opposite/hypotenuse. It's abbreviated as the ratio of the side opposite to angle θ and the hypotenuse.
Q2. What is the value of sin(90°)?
- 0
- √3/2
- 0.5
- 1 ✓ (correct)
Explanation: sin(90°) = 1 because at 90°, the opposite side equals the hypotenuse.
Q3. tan(θ) equals:
- sin(θ)/cos(θ) ✓ (correct)
- sin(θ) × cos(θ)
- sin(θ) + cos(θ)
- cos(θ)/sin(θ)
Explanation: tan(θ) = sin(θ)/cos(θ) = opposite/adjacent.
Q4. The value of cos(0°) is:
- √3/2
- 1 ✓ (correct)
- 0.5
- 0
Explanation: cos(0°) = 1 because at 0°, the adjacent side equals the hypotenuse.
Q5. Which of the following is an identity?
- sin(θ) × cos(θ) = 1
- sin(θ) + cos(θ) = 1
- sin²(θ) + cos²(θ) = 1 ✓ (correct)
- sin(θ) - cos(θ) = 0
Explanation: sin²(θ) + cos²(θ) = 1 is the fundamental Pythagorean identity in trigonometry.
Q6. In a right triangle with angle 30°, if the hypotenuse is 10, the side opposite to 30° is:
- 5√3
- 10
- 10/√3
- 5 ✓ (correct)
Explanation: sin(30°) = 1/2 = opposite/hypotenuse. So opposite = 10 × (1/2) = 5.
Q7. The angle of elevation is measured from:
- Above the horizontal ✓ (correct)
- Below the horizontal
- The vertical downward
- Above the vertical
Explanation: The angle of elevation is the angle above the horizontal when looking upward at an object.
Q8. What is tan(45°)?
- 1/√2
- 1 ✓ (correct)
- √3
- 0
Explanation: tan(45°) = 1 because in a 45-45-90 triangle, the opposite and adjacent sides are equal.
Q9. If sin(θ) = 3/5, then cos(θ) could be:
- 5/3
- 2/5
- 4/5 ✓ (correct)
- 3/5
Explanation: Using sin²(θ) + cos²(θ) = 1: (3/5)² + cos²(θ) = 1, so cos²(θ) = 1 - 9/25 = 16/25, thus cos(θ) = 4/5.
Q10. cot(θ) equals:
- tan(θ)
- sin(θ)
- cos(θ)
- 1/tan(θ) ✓ (correct)
Explanation: cot(θ) = 1/tan(θ) = cos(θ)/sin(θ) = adjacent/opposite.
Q11. In a right-angled triangle, sin A =
- Opposite / Hypotenuse ✓ (correct)
- Opposite / Adjacent
- Hypotenuse / Opposite
- Adjacent / Hypotenuse
Explanation: Sin A = Opposite / Hypotenuse, which is one of the basic trigonometric ratios.
Q12. If sin A = 3/5 and angle A is acute, then cos A =
- 5/4
- 4/5 ✓ (correct)
- 3/4
- 5/3
Explanation: Using sin^2 A + cos^2 A = 1: (3/5)^2 + cos^2 A = 1, so cos^2 A = 16/25, thus cos A = 4/5.
Q13. The value of sin 0 degrees is:
- 1/2
- 1
- 0 ✓ (correct)
- -1
Explanation: sin 0 = 0, which is a standard trigonometric value.
Q14. tan A = cot A when A =
- 60 degrees
- 90 degrees
- 30 degrees
- 45 degrees ✓ (correct)
Explanation: tan A = cot A when tan A = 1/tan A, which means tan^2 A = 1, so A = 45 degrees.
Q15. If sin A = cos B and A and B are acute angles, then A + B =
- 90 degrees ✓ (correct)
- 45 degrees
- 180 degrees
- 60 degrees
Explanation: If sin A = cos B, then A and B are complementary angles, so A + B = 90 degrees.
Q16. The value of sec 60 degrees is:
- sqrt(3)/2
- 2 ✓ (correct)
- sqrt(2)
- 2/sqrt(3)
Explanation: sec 60 = 1/cos 60 = 1/(1/2) = 2.
Q17. If tan A = 1/sqrt(3), then A =
- 90 degrees
- 45 degrees
- 30 degrees ✓ (correct)
- 60 degrees
Explanation: tan 30 = 1/sqrt(3), so A = 30 degrees.
Q18. sin^2 A + cos^2 A =
- 0
- -1
- 2
- 1 ✓ (correct)
Explanation: sin^2 A + cos^2 A = 1 is the fundamental trigonometric identity.
Q19. If a ladder of length 10 m leans against a wall making 60 degrees with the ground, the height at which it touches the wall is:
- 5sqrt(3) m ✓ (correct)
- 5 m
- 10 m
- 10sqrt(3) m
Explanation: Height = 10 x sin 60 = 10 x sqrt(3)/2 = 5sqrt(3) m.
Q20. The angle of elevation from a point on the ground to the top of a 20 m building is 30 degrees. The distance from the point to the base of the building is:
- 10 m
- 20sqrt(3) m ✓ (correct)
- 40/sqrt(3) m
- 10sqrt(3) m
Explanation: Distance = 20 / tan 30 = 20 / (1/sqrt(3)) = 20sqrt(3) m.
Frequently Asked Questions
What are the trigonometric ratios for 30°, 45°, and 60°?
For 30°: sin = 1/2, cos = √3/2, tan = 1/√3. For 45°: sin = cos = 1/√2, tan = 1. For 60°: sin = √3/2, cos = 1/2, tan = √3. These standard angles are frequently used in calculations.
How are angles of elevation and depression used in real-world problems?
Angles of elevation (when looking up) and depression (when looking down) help solve problems involving heights and distances. For example, finding the height of a building from a known distance using the angle of elevation.
More Class 10 Mathematics MCQs
🤖 Stuck on any of these? Ask Syllab's free AI Tutor to explain step by step →