Speed vs Acceleration — Difference (with Table & FAQs)

Speed vs Acceleration compared side by side — a 6-row comparison table, 4 key points and 7 exam FAQs. Class 9 Physics, free and no sign-up.

Speed vs Acceleration — Difference (with Table & FAQs)

Speed vs Acceleration compared side by side — a 6-row comparison table, 4 key points and 7 exam FAQs. Class 9 Physics, free and no sign-up.

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TL;DR: Speed vs Acceleration compared side by side — a 6-row comparison table, 4 key points and 7 exam FAQs. Class 9 Physics, free and no sign-up.

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The main difference between Speed and Acceleration: Speed is the rate of change of distance. Acceleration is the rate of change of velocity.

Speed vs Acceleration — Comparison Table

BasisSpeedAcceleration
DefinitionDistance covered per unit timeChange in velocity per unit time
TypeScalar quantityVector quantity
SI Unitm/sm/s²
FormulaSpeed = Distance / Timea = (v - u) / t
Can be zeroOnly when object at restWhen velocity is constant
ExampleCar traveling at 60 km/hCar speeding up from rest

Key Points

  • Speed tells how fast, acceleration tells how quickly velocity changes
  • Constant speed does not mean zero acceleration if direction changes
  • Negative acceleration is deceleration
  • Both affect motion but in different ways

Speed — how fast

Speed tells you how much distance an object covers in unit time: speed = distance ÷ time. Its SI unit is metre per second (m/s), and it is a scalar, so it has size but no direction.

Speed answers the question 'how fast is it going right now?' A number on its own is enough — 20 m/s is a complete statement of speed.

Acceleration — how quickly the velocity changes

Acceleration is the rate of change of velocity: a = (v − u) ÷ t, where u is the initial velocity and v the final velocity. Its SI unit is metre per second squared (m/s²), and it is a vector, so direction matters.

Acceleration answers a different question: 'how quickly is the motion changing?' An object can have a huge speed and zero acceleration — a train cruising steadily at 100 km/h — or zero speed and a large acceleration, like a ball at the exact top of its flight, momentarily still but still accelerating downward at 9.8 m/s².

The three equations of motion

These apply only to uniformly accelerated motion in a straight line. Almost every numerical in the chapter uses one of them.

  • v = u + at — relates velocity and time.
  • s = ut + ½at² — relates distance and time.
  • v² = u² + 2as — relates velocity and distance, with no time term. Use this one when time is not given and not asked for.
  • Here u is initial velocity, v final velocity, a acceleration, t time and s distance travelled.
  • For a body falling freely, replace a with g = 9.8 m/s² (often taken as 10 m/s² for quick working). For a body thrown upward, g is negative because it opposes the motion.

Positive, negative and zero acceleration

Acceleration is positive when velocity increases in the direction of motion — the object speeds up. It is negative when velocity decreases; this is called retardation or deceleration, and braking is the everyday case.

Acceleration is zero when velocity does not change at all, which means the object is at rest or moving with uniform velocity in a straight line. Zero acceleration does not mean zero speed, and that distinction is worth marks.

Reading motion graphs

On a distance-time graph, the slope gives the speed. A straight line means uniform speed; a curve means the speed is changing; a horizontal line means the object is at rest.

On a velocity-time graph, the slope gives the acceleration and the area under the graph gives the distance travelled. A horizontal line means uniform velocity and therefore zero acceleration; a straight sloping line means uniform acceleration. Being asked to find distance from the area under a velocity-time graph is a standard exam question.

Speed vs Acceleration — Worked Examples

  • A car speeding up from 10 m/s to 30 m/s in 4 s — a = (30 − 10) ÷ 4 = 5 m/s². Its speed changed; the acceleration describes how quickly.
  • A train cruising at a steady 100 km/h — High speed, but zero acceleration — the velocity is not changing.
  • A ball at the highest point of a throw — Speed is zero for an instant, but acceleration is 9.8 m/s² downward. Speed and acceleration are genuinely independent.
  • A car braking from 20 m/s to rest in 5 s — a = (0 − 20) ÷ 5 = −4 m/s². The negative sign means retardation.

Common Mistakes Students Make

  • Thinking zero speed means zero acceleration. A ball at the top of its flight disproves it.
  • Writing the unit of acceleration as m/s. It is m/s².
  • Using the equations of motion when the acceleration is not uniform. They only apply to uniform acceleration.
  • Forgetting that g is negative for a body thrown upward and positive for a body falling.
  • Confusing the slope and the area on a velocity-time graph: slope gives acceleration, area gives distance.

Diagrams

Velocity-time graph showing slope and areaGraph demonstrating that slope represents acceleration and the area under the line represents distance.time (s) →velocity(m/s)ΔvΔtSLOPE = ACCELERATIONAREA = DISTANCEslope 0 → zero accelerationuniform velocitySlope gives acceleration; area under the line gives distance. Do not swap them.
The slope of a velocity-time graph is the acceleration, and the area beneath it is the distance travelled. A sloping line means uniform acceleration; a horizontal line means constant velocity and therefore zero acceleration — even though the speed is high.

Where This Shows Up in Real Life

Why 0-60 figures describe acceleration, not speed

A car advertised as "0 to 100 km/h in 7 seconds" is being sold on its acceleration, not its top speed. Two cars with the same maximum speed can feel utterly different because one reaches it far quicker. Acceleration is what you physically feel pressing you into the seat; steady speed, however high, feels like nothing at all, which is why a smooth aircraft at 900 km/h feels still.

Free fall and why everything falls together

Near the Earth’s surface every freely falling body accelerates at about 9.8 m/s² regardless of its mass, because gravity pulls harder on a heavier object but that object also resists acceleration more, and the two effects cancel exactly. A feather falls slower only because of air resistance; in a vacuum a feather and a hammer land together, as demonstrated on the Moon during Apollo 15.

Stopping distance and road safety

Braking supplies a retardation, and from v² = u² + 2as the stopping distance depends on the SQUARE of the initial speed. Doubling your speed roughly quadruples the distance needed to stop. This single relationship is the reason speed limits fall so sharply near schools, and it is a far more persuasive argument than any slogan.

Circular motion: changing velocity at constant speed

A stone whirled on a string at a steady rate has constant speed but continuously changing direction, so its velocity is changing and it is therefore accelerating. The acceleration points towards the centre and is supplied by the tension in the string. Cut the string and the stone flies off along the tangent — direct evidence that a force was needed simply to keep it turning.

Solved Numericals — Step by Step

Problem 1. A body starting from rest attains a velocity of 30 m/s in 6 s. Find its acceleration and the distance covered.

  1. u = 0, v = 30 m/s, t = 6 s.
  2. a = (v − u) ÷ t = (30 − 0) ÷ 6 = 5 m/s².
  3. s = ut + ½at² = 0 + ½ × 5 × 6² = ½ × 5 × 36.
  4. s = 90 m.

Answer: Acceleration 5 m/s², distance 90 m.

Problem 2. A car moving at 20 m/s is brought to rest over 50 m. Find its retardation using v² = u² + 2as.

  1. u = 20 m/s, v = 0, s = 50 m.
  2. 0² = 20² + 2 × a × 50
  3. 0 = 400 + 100a
  4. a = −400 ÷ 100 = −4 m/s².

Answer: Retardation of 4 m/s². Note this equation is the one to use when time is neither given nor asked for.

Problem 3. A stone is dropped from a height of 45 m. Find the time to reach the ground and its striking velocity. Take g = 10 m/s².

  1. u = 0, s = 45 m, a = g = 10 m/s².
  2. s = ut + ½at² → 45 = 0 + ½ × 10 × t² = 5t².
  3. t² = 9, so t = 3 s.
  4. v = u + at = 0 + 10 × 3 = 30 m/s.

Answer: It takes 3 s and strikes the ground at 30 m/s.

Problem 4. A bus accelerates uniformly from 10 m/s to 25 m/s in 5 s. Find the acceleration and the distance travelled.

  1. a = (25 − 10) ÷ 5 = 15 ÷ 5 = 3 m/s².
  2. s = ut + ½at² = 10 × 5 + ½ × 3 × 25
  3. s = 50 + 37.5.

Answer: Acceleration 3 m/s²; distance 87.5 m. Check with v² = u² + 2as: 625 = 100 + 2(3)(87.5) = 100 + 525 = 625. Consistent.

Board-Style Questions with Model Answers

Define speed and acceleration. State their SI units and whether each is a scalar or a vector. (3 marks)

Speed is the distance travelled by a body per unit time. Its SI unit is the metre per second (m/s) and it is a scalar quantity, having magnitude but no direction. Acceleration is the rate of change of velocity of a body, given by the change in velocity divided by the time taken, a = (v − u)/t. Its SI unit is the metre per second squared (m/s²) and it is a vector quantity, having both magnitude and direction. The essential distinction is that speed tells you how fast a body is moving, whereas acceleration tells you how quickly that motion is changing.

Write the three equations of motion and state the condition under which they are valid. (3 marks)

The three equations are v = u + at, which relates velocity and time; s = ut + ½at², which relates distance and time; and v² = u² + 2as, which relates velocity and distance without involving time. Here u is the initial velocity, v the final velocity, a the acceleration, t the time taken and s the distance travelled. They are valid only for motion in a straight line with UNIFORM acceleration, that is when the acceleration does not change during the interval considered. If the acceleration varies, or the path is curved, these equations give incorrect results and calculus-based methods are required instead.

Can a body have zero velocity and non-zero acceleration? Explain with an example. (2 marks)

Yes. Velocity and acceleration are independent quantities, and a body can have one without the other. The standard example is a ball thrown vertically upward. At the highest point of its flight the ball is momentarily at rest, so its velocity is zero, but gravity continues to act on it throughout, so its acceleration is 9.8 m/s² directed downward. It is precisely because the acceleration is non-zero at that instant that the ball does not remain suspended but immediately begins to fall.

Draw and describe what the slope and area of a velocity-time graph represent. (3 marks)

On a velocity-time graph, velocity is plotted on the vertical axis and time on the horizontal axis. The SLOPE of the graph represents the acceleration of the body, because slope is change in velocity divided by change in time, which is the definition of acceleration. A horizontal line therefore means zero acceleration and uniform velocity, while a straight sloping line means uniform acceleration. The AREA enclosed between the graph and the time axis represents the distance travelled, since velocity multiplied by time gives distance. For uniformly accelerated motion the area is a trapezium, and computing it gives the same result as the equation s = ut + ½at².

A train starting from rest accelerates uniformly at 2 m/s² for 10 s. Find its final velocity and the distance covered. (3 marks)

Here the initial velocity u is 0 since the train starts from rest, the acceleration a is 2 m/s² and the time t is 10 s. Using the first equation of motion, v = u + at gives v = 0 + 2 × 10 = 20 m/s, so the final velocity is 20 m/s. Using the second equation, s = ut + ½at² gives s = 0 × 10 + ½ × 2 × 10² = ½ × 2 × 100 = 100 m, so the distance covered is 100 m. This can be checked with the third equation: v² = u² + 2as gives 400 = 0 + 2 × 2 × 100 = 400, which is consistent.

Assertion–Reason Questions (CBSE Format)

For each question choose: (a) both A and R are true and R is the correct explanation of A; (b) both are true but R is not the correct explanation; (c) A is true but R is false; (d) A is false but R is true.

1. Assertion (A): A body can have zero speed and non-zero acceleration.
Reason (R): At the highest point of its flight a body thrown upward is momentarily at rest while gravity still acts.

Answer: (a) — Both are true and the reason is the standard example proving the assertion. Speed and acceleration are independent quantities.

2. Assertion (A): Uniform circular motion is accelerated motion.
Reason (R): The direction of the velocity changes continuously even though the speed is constant.

Answer: (a) — Both are true and correctly linked. Acceleration responds to any change in velocity, and direction is part of velocity.

3. Assertion (A): The equations of motion apply to all kinds of motion.
Reason (R): They relate the quantities u, v, a, t and s.

Answer: (c) — The assertion is false — they hold only for straight-line motion with UNIFORM acceleration. The reason is a true but incomplete statement that does not rescue it.

4. Assertion (A): Doubling the speed of a car roughly quadruples its stopping distance.
Reason (R): From v² = u² + 2as, the stopping distance depends on the square of the initial speed.

Answer: (a) — Both are true and the reason explains the assertion. This is the physics behind lower speed limits near schools.

Quick Self-Check

Q1. The SI unit of acceleration is:

  • A. m/s
  • B. m/s²
  • C. km/h
  • D. N

Answer: B. m/s² — Acceleration is the change in velocity (m/s) per unit time (s), giving m/s².

Q2. A body starts from rest and reaches 20 m/s in 5 s. Its acceleration is:

  • A. 100 m/s²
  • B. 4 m/s²
  • C. 0.25 m/s²
  • D. 25 m/s²

Answer: B. 4 m/s² — a = (v − u) ÷ t = (20 − 0) ÷ 5 = 4 m/s².

Q3. Which equation does NOT contain time?

  • A. v = u + at
  • B. s = ut + ½at²
  • C. v² = u² + 2as
  • D. All contain time

Answer: C. v² = u² + 2as — v² = u² + 2as relates velocity to distance directly, which is why it is used when time is neither given nor asked for.

Q4. On a velocity-time graph, the area under the curve represents:

  • A. Acceleration
  • B. Speed
  • C. Distance travelled
  • D. Time

Answer: C. Distance travelled — The slope gives acceleration; the area under the graph gives the distance travelled.

Key Terms Glossary

Speed
Distance travelled per unit time. Scalar. SI unit m/s.
Velocity
Displacement per unit time. Vector — it carries a direction.
Acceleration
Rate of change of velocity, a = (v − u)/t. Vector. SI unit m/s².
Uniform acceleration
Acceleration that stays constant in magnitude and direction. Required for the three equations of motion.
Retardation
Negative acceleration — the velocity decreases with time, as during braking.
Equations of motion
v = u + at, s = ut + ½at², v² = u² + 2as. Valid only for uniform acceleration in a straight line.
g
Acceleration due to gravity, about 9.8 m/s² near the Earth’s surface (often taken as 10 for quick working).
Free fall
Motion under gravity alone, with air resistance neglected. Independent of the body’s mass.
Distance-time graph
Its SLOPE gives the speed. A horizontal line means the body is at rest.
Velocity-time graph
Its SLOPE gives acceleration; the AREA under it gives distance travelled.
Initial velocity (u)
The velocity at the start of the interval considered. Zero if the body starts from rest.
Uniform velocity
Constant speed in a fixed straight-line direction, so acceleration is zero.

One-Minute Revision

  • SPEED = how fast (m/s, scalar). ACCELERATION = how fast the velocity CHANGES (m/s², vector).
  • Zero speed does NOT mean zero acceleration — the ball at the top of a throw proves it.
  • Three equations: v = u + at, s = ut + ½at², v² = u² + 2as. UNIFORM acceleration only.
  • Use v² = u² + 2as when time is neither given nor asked for.
  • Free fall: g ≈ 9.8 m/s² regardless of mass. Downward positive when falling, negative when thrown up.
  • Velocity-time graph: SLOPE = acceleration, AREA = distance. Do not swap them.
  • Retardation is just negative acceleration — quote the magnitude and state the direction.
  • Stopping distance goes as the SQUARE of speed: double the speed, roughly quadruple the distance.

Syllabus reference: NCERT Class 9 Science, Chapter 8 — Motion.

Frequently Asked Questions

What is the difference between speed and acceleration?

Speed is the rate at which an object covers distance (distance ÷ time). Acceleration is the rate at which an object’s velocity changes (change in velocity ÷ time).

What are the units of speed and acceleration?

Speed is measured in metres per second (m/s). Acceleration is measured in metres per second squared (m/s²).

Does constant speed mean zero acceleration?

If an object moves in a straight line at constant speed, its acceleration is zero because its velocity is not changing.

Can an object have zero speed but non-zero acceleration?

Yes. A ball thrown straight up is momentarily at rest at the highest point of its flight, so its speed is zero, but gravity is still acting on it and its acceleration is 9.8 m/s² downward. This is the standard example used to show that speed and acceleration are independent.

What is negative acceleration called?

Retardation, or deceleration. It occurs when the velocity decreases with time, such as when a vehicle brakes. The acceleration acts in the direction opposite to the motion.

Can an object moving at constant speed be accelerating?

Yes, if its direction is changing. An object moving in a circle at a steady rate has constant speed but continuously changing velocity, so it is accelerating. Acceleration responds to any change in velocity, including a change of direction alone.

When do the equations of motion not apply?

They apply only to motion with uniform acceleration along a straight line. If the acceleration is changing, or the path is curved, these three equations give wrong answers and calculus-based methods are needed instead.

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